12. Speed, time, distance and average speed
Free study material · concepts, shortcuts & solved questions
Distance = speed × time. Convert km/h to m/s by multiplying 5/18 and m/s to km/h by 18/5. For equal distances at speeds u and v, average speed = 2uv/(u+v); for equal times, arithmetic mean applies.
Method before formula Use a distance-time table. Relative speed is the sum for opposite directions and the difference for the same direction. A speed increase changes time inversely, not by the same percentage. |
Formula and decision table
Example | Result |
72 km/h | 20 m/s |
Equal distances at 30 and 60 | Average=40 km/h |
Speed +25% | Time multiplier=1/1.25; time falls 20% |
Worked understanding
A reliable solution has five visible moves: identify the data, choose the base or unit, write the rule, substitute carefully, and check the size of the answer. The examples in this chapter are deliberately small so that the method remains visible.
Calculation discipline Before pressing ahead, state the denominator or unit in words. For example: profit on CP, discount on MP, average over number of items, speed in metres per second, and probability over the fixed sample space. |
Solved examples from this chapter
Question focus | Correct move | Answer |
72 km/h equals: | 72×5/18=20. | B. 20 m/s |
Equal distances at 30 and 60 km/h average: | 2×30×60/90=40. | B. 40 |
For opposite directions, relative speed is: | The separation changes at the sum. | B. Sum |
What an examiner is testing
The options around Speed, time, distance and average speed usually represent a wrong base, a missed conversion, a sign error or a shortcut used outside its condition. Say the base and unit before calculating, estimate the result, and use substitution or a reverse operation as the final check.
Step-by-step answer construction
Example 1: 72 km/h equals: First identify the requested quantity and its base or unit. Apply the chapter rule, keep the operation visible, estimate the expected range, and compare the result with the options. The correct answer is 20 m/s, because 72×5/18=20.
Example 2: Equal distances at 30 and 60 km/h average: First identify the requested quantity and its base or unit. Apply the chapter rule, keep the operation visible, estimate the expected range, and compare the result with the options. The correct answer is 40, because 2×30×60/90=40.
Example 3: For opposite directions, relative speed is: First identify the requested quantity and its base or unit. Apply the chapter rule, keep the operation visible, estimate the expected range, and compare the result with the options. The correct answer is Sum, because The separation changes at the sum.
Chapter practice
1. 72 km/h equals:
(A) 15 m/s (B) 20 m/s (C) 25 m/s (D) 30 m/s
Answer: B. 20 m/s | Explanation: 72×5/18=20.
2. Equal distances at 30 and 60 km/h average:
(A) 35 (B) 40 (C) 45 (D) 50
Answer: B. 40 | Explanation: 2×30×60/90=40.
3. For opposite directions, relative speed is:
(A) Difference (B) Sum (C) Product (D) Average
Answer: B. Sum | Explanation: The separation changes at the sum.
SSC CGL speed and trap clinic
For Speed, time, distance and average speed, speed comes after classification. Before calculating, say aloud what the number means, what the denominator is, and what unit the answer must carry. Then use the nearest-option check to catch a sign, base or conversion error.
Checkpoint | What to verify | Typical SSC mistake |
Base | Which quantity is the base in Speed, time, distance and average speed? | Using selling price instead of cost price, or part instead of total |
Unit | Are time, distance, area and rate in compatible units? | Mixing hours with minutes or km/h with m/s |
Direction | Should the answer increase, decrease or stay bounded? | Accepting an impossible negative length or probability above 1 |
Estimate | What range should the answer lie in before exact work? | Trusting a long calculation that is far from the options |
Reverse check | Can the answer be substituted back into the condition? | Stopping at an algebraic value without verification |
Mini decision drill
1. Write the first operation you would perform in a Speed, time, distance and average speed question and why.
2. State the most dangerous denominator or unit in this chapter.
3. Give one condition under which a shortcut would be invalid.
4. Create a small numerical example and verify it by a second method.
Revision evidence Do not tick this chapter because you recognised the formula. Tick it only after you solve one direct question, one altered-condition question and one mixed-paper question correctly. |