RCC Slabs, Columns and Footings
What to remember
- One-way slab: ly/lx > 2, main steel in the short direction; two-way slab: ly/lx ≤ 2, steel in both directions with moments Mx = αx wu lx² and My = αy wu lx².
- Short column: le/D < 12. Axial strength Pu = 0.4 fck Ac + 0.67 fy Asc. Longitudinal steel must be between 0.8% and 6% of the gross area.
- Footing design: size the base from the unfactored load and safe bearing capacity; check one-way shear at distance d and two-way (punching) shear at d/2 from the column face; bending moment is taken at the column face.
1. Slabs
A slab is a flat plate supported on beams or walls. Its depth is small compared with the span, so it is designed for a 1 m wide strip.
Load calculation (per m²): self weight = thickness (m) × 25 kN/m³; add floor finish, plaster and live load. Factored load wu = 1.5 × (DL + LL). Example: D = 150 mm gives 3.75 kN/m²; with finish 1.0 and live load 3.0 the factored load is 1.5 × 7.75 = 11.6 kN/m².
Effective span: the lesser of centre-to-centre distance of supports and clear span + effective depth.
One-way slab: ly/lx > 2. For a simply supported slab, Mu = wu l² / 8 and Vu = wu l / 2. Main bars are along the short span at the bottom; distribution (secondary) bars are placed perpendicular to them. Example: wu = 12 kN/m², l = 4 m gives Mu = 12 × 16/8 = 24 kN·m per metre width.
Two-way slab: ly/lx ≤ 2. IS 456 gives moment coefficients αx, αy for different edge conditions. For a simply supported square slab with corners free to lift, αx = αy = 0.062. Example: wu = 10 kN/m², lx = 4 m: Mx = 0.062 × 10 × 16 = 9.92 kN·m per metre. Where a slab edge is restrained and corners are prevented from lifting, torsion reinforcement is provided at corners over a length of lx/5, in four layers, each with area equal to three-quarters of the steel required for the maximum mid-span moment.
Cantilever slab: main steel at the top; basic l/d is 7.
Detailing rules for slabs:
| Item | Rule |
|---|---|
| Minimum steel (of gross area) | 0.15% for Fe 250; 0.12% for Fe 415 and Fe 500 |
| Maximum spacing, main bars | 3d or 300 mm, whichever is less |
| Maximum spacing, distribution bars | 5d or 450 mm, whichever is less |
| Maximum bar diameter | D/8 |
| Basic l/d (simply supported / continuous / cantilever) | 20 / 26 / 7 |
| Cover (mild exposure) | 20 mm |
Slabs are generally safe in shear and no shear reinforcement is normally provided if τv is below τc (with factor k for thin slabs).
Flat slab: a slab supported directly on columns without beams. Drop panels (thickened slab) and column heads (capitals) reduce punching shear and negative moments. The critical section for punching shear is at d/2 from the column (or capital) face. Advantages: flat soffit, easy formwork, more headroom. Disadvantage: low resistance to lateral load.
2. Columns
A column is a vertical compression member whose effective length exceeds three times its least lateral dimension (a shorter one is a pedestal).
Effective length le (theoretical values for a column of length L):
| End conditions | le |
|---|---|
| Both ends fixed | 0.65 L |
| One end fixed, other hinged | 0.80 L |
| Both ends hinged | 1.0 L |
| One end fixed, other free (cantilever) | 2.0 L |
Short and long columns: short if le/D < 12 (fails by crushing); long (slender) if le/D ≥ 12 (fails by buckling). For slender columns an additional moment Ma = Pu D/2000 × (le/D)² is added. Example: Pu = 1000 kN, D = 400 mm, le = 6 m, le/D = 15 so Ma = 1000 × 0.4/2000 × 225 = 45 kN·m.
Minimum eccentricity: emin = L/500 + D/30, not less than 20 mm. Example: L = 3 m, D = 300 mm gives 6 + 10 = 16 mm, so use 20 mm.
Axial strength of a short column (emin ≤ 0.05 D): Pu = 0.4 fck Ac + 0.67 fy Asc, where Ac is the concrete area (gross minus steel). Example: 400 × 400 mm, M20, Fe 415, Asc = 1% = 1600 mm². Ac = 158,400 mm². Pu = 0.4 × 20 × 158,400 + 0.67 × 415 × 1600 = 1267 + 445 kN ≈ 1712 kN.
Working stress form: P = σcc Ac + σsc Asc, with steel stress limited using the modular ratio.
Detailing of columns:
- Longitudinal steel: minimum 0.8%, maximum 6% of gross area (about 4% recommended where bars lap). Minimum 4 bars in a rectangular column and 6 in a circular column. Minimum bar diameter 12 mm.
- Lateral ties: diameter not less than one-quarter of the largest longitudinal bar and not less than 6 mm. Pitch is the least of (a) the least lateral dimension, (b) 16 times the smallest longitudinal bar diameter and (c) 300 mm.
- Cover: 40 mm or bar diameter, whichever is greater (nominal).
- Helical (spiral) columns: pitch not more than 75 mm and not more than one-sixth of core diameter; not less than 25 mm and not less than 3 times the wire diameter. Strength of a helically reinforced column is taken as 1.05 times that of a tied column. Helical columns are more ductile.
Pedestal: a compression member whose height does not exceed three times its least lateral dimension.
3. Footings
A footing spreads the column load over a wide soil area so that the bearing pressure is less than the safe bearing capacity (SBC).
Types: isolated (square, rectangular, circular; sloped or stepped), wall (strip) footing, combined footing (two or more columns), strap (cantilever) footing, raft or mat, and pile foundation.
Sizing an isolated footing (use unfactored loads): A = (P + about 10% for self weight) / SBC. Example: P = 900 kN, SBC = 150 kN/m²: A = 1.1 × 900/150 = 6.6 m². For structural design use factored load/area (net upward pressure); self weight of the footing is ignored in bending and shear because it is balanced by the soil reaction.
Pressure under eccentric load: p = (P/A)(1 ± 6e/L) for eccentricity e along length L. There is no tension if e ≤ L/6 (middle-third rule). Example: P = 600 kN, 2 m × 2 m, e = 0.2 m: p = 150 × (1 ± 0.6) = 240 and 60 kN/m².
Design checks:
| Check | Critical section |
|---|---|
| Bending moment | At the face of the column (or wall) |
| One-way (beam) shear | At distance d from the column face |
| Two-way (punching) shear | At d/2 from the column face, around the perimeter |
| Development length | From critical section outward |
| Bearing at column base | Allowable 0.45 fck √(A1/A2), where √(A1/A2) is limited to 2 |
Permissible punching shear stress τc' = ks τc, where ks = 0.5 + βc (βc = short side / long side of column), ks ≤ 1, and τc = 0.25 √fck. For M20 and a square column, τc' = 0.25 × √20 = 1.12 N/mm².
Footing rules: minimum cover 50 mm (earth-face concrete); minimum edge thickness 150 mm on soil (300 mm on piles); dowels from column into footing have minimum area of 0.5% of the column cross-section.
Combined footing: used when columns are close or one column is near a property line. The centroid of the footing area should coincide with the resultant of column loads. Example: loads of 600 kN and 400 kN, 4 m apart: resultant is 4 × 400/1000 = 1.6 m from the heavier column.
Strap footing: two footings joined by a strap beam so that an eccentric edge column does not tilt. Raft: used for weak soil or when isolated footings would cover more than about half the plan area.
Exam traps
- One-way slab limit is ly/lx > 2; at exactly 2 the slab is two-way.
- Slab minimum steel is 0.15% for Fe 250 but 0.12% for Fe 415 and Fe 500.
- Distribution bar limit is 5d or 450 mm, but main bar limit is 3d or 300 mm.
- Column slenderness limit is le/D = 12; do not confuse with L/r values of steel columns.
- Short-column formula uses 0.4 fck and 0.67 fy (not 0.446 and 0.87).
- Footing bending is at the column face; punching shear is at d/2 and one-way shear at d.
- Footing size uses working loads; footing thickness design uses factored loads.
- Fixed-free column has le = 2L; both ends fixed has 0.65 L.
One-liners
- 1. A slab is one-way if ly/lx > 2.
- 2. Maximum bar spacing: 3d or 300 mm (main); 5d or 450 mm (distribution).
- 3. Minimum slab steel is 0.12% of gross area for Fe 415.
- 4. Maximum bar diameter in a slab is D/8.
- 5. Short column means le/D < 12.
- 6. Minimum eccentricity is L/500 + D/30 or 20 mm, whichever is greater.
- 7. Pu = 0.4 fck Ac + 0.67 fy Asc.
- 8. Column steel: minimum 0.8%, maximum 6%.
- 9. Tie spacing is the least of least lateral dimension, 16 φ and 300 mm.
- 10. Punching shear section is at d/2; one-way shear section is at d.
- 11. ks = 0.5 + βc, not more than 1.
- 12. Middle-third rule: e ≤ L/6 avoids tension in soil pressure.
Practice questions
A rectangular slab supported on all four edges behaves as a one-way slab when ly/lx is:
- Less than 1.5
- Greater than 2
- Equal to 1
- Between 1 and 2
Answer
B. Greater than 2
For ly/lx > 2 bending in the long direction is negligible, so main steel runs in the short span.
A simply supported slab of 3 m span needs a minimum effective depth (basic l/d = 20) of:
- 150 mm
- 100 mm
- 300 mm
- 200 mm
Answer
A. 150 mm
d = 3000/20 = 150 mm.
For a slab of overall depth 150 mm using Fe 415 steel, the minimum steel per metre width is:
- 120 mm²
- 225 mm²
- 180 mm²
- 300 mm²
Answer
C. 180 mm²
0.12% × 1000 × 150 = 180 mm².
The maximum spacing of main bars in a slab with effective depth 120 mm is:
- 360 mm
- 450 mm
- 240 mm
- 300 mm
Answer
D. 300 mm
Lesser of 3d = 360 mm and 300 mm is 300 mm.
The maximum spacing of distribution bars in a slab with effective depth 80 mm is:
- 300 mm
- 400 mm
- 450 mm
- 240 mm
Answer
B. 400 mm
Lesser of 5d = 400 mm and 450 mm is 400 mm.
The maximum diameter of reinforcing bar allowed in a slab of overall thickness 160 mm is:
- 20 mm
- 25 mm
- 16 mm
- 32 mm
Answer
A. 20 mm
Bar diameter should not exceed D/8 = 20 mm.
A simply supported one-way slab of 4 m span carries a factored load of 12 kN/m². The design moment per metre width is:
- 48 kN·m
- 36 kN·m
- 24 kN·m
- 12 kN·m
Answer
C. 24 kN·m
Mu = wu l²/8 = 12 × 16/8 = 24 kN·m.
A 150 mm slab (25 kN/m³) carries finish 1.0 kN/m² and live load 3.0 kN/m². The factored load is nearly:
- 10.1 kN/m²
- 7.75 kN/m²
- 12.4 kN/m²
- 11.6 kN/m²
Answer
D. 11.6 kN/m²
DL = 3.75 + 1.0; with LL 3.0 total 7.75; 1.5 × 7.75 = 11.6.
For a simply supported square two-way slab (αx = 0.062) with wu = 10 kN/m² and lx = 4 m, Mx per metre is nearly:
- 9.92 kN·m
- 20 kN·m
- 5 kN·m
- 12.5 kN·m
Answer
A. 9.92 kN·m
Mx = 0.062 × 10 × 4² = 9.92 kN·m.
Torsion reinforcement at corners of a two-way slab is provided over a length of:
- One-tenth of the longer span
- One-fifth of the shorter span
- One-third of the shorter span
- Half of the longer span
Answer
B. One-fifth of the shorter span
Corner torsion steel extends lx/5 in each direction.
The main purpose of distribution bars in a one-way slab is to:
- Increase the neutral axis depth
- Carry the entire bending moment
- Distribute loads and resist shrinkage and temperature stresses
- Resist shear
Answer
C. Distribute loads and resist shrinkage and temperature stresses
Distribution steel runs at right angles to main bars and controls cracks.
In a cantilever slab the main reinforcement is placed:
- Near the bottom face
- At mid depth
- Equally top and bottom
- Near the top face
Answer
D. Near the top face
Hogging moment causes tension at the top.
In a flat slab, the critical section for punching shear is at a distance from the column face of:
- d/2
- Zero
- 2d
- d
Answer
A. d/2
Punching shear perimeter is taken at d/2 from the column or capital face.
A column is classed as short when the ratio of effective length to least lateral dimension is:
- Less than 3
- Less than 12
- More than 12
- Equal to 20
Answer
B. Less than 12
Short columns have le/D < 12; slender columns have le/D ≥ 12.
The minimum eccentricity for a column of length 3.0 m and lateral dimension 300 mm is:
- 6 mm
- 10 mm
- 20 mm
- 16 mm
Answer
C. 20 mm
L/500 + D/30 = 6 + 10 = 16 mm, but not less than 20 mm.
A short 400 mm × 400 mm column has fck = 20, fy = 415 and 1% steel (1600 mm²). The axial strength Pu is nearly:
- 1267 kN
- 1500 kN
- 2200 kN
- 1712 kN
Answer
D. 1712 kN
0.4 × 20 × 158,400 + 0.67 × 415 × 1600 = 1267 + 445 = 1712 kN.
The percentage of longitudinal steel in a column should lie between:
- 0.5% and 4%
- 0.15% and 2%
- 0.8% and 6%
- 1% and 8%
Answer
C. 0.8% and 6%
IS 456 gives minimum 0.8% and maximum 6% of the gross area.
The minimum number of longitudinal bars in a circular column is:
- 4
- 8
- 3
- 6
Answer
D. 6
Rectangular columns need 4, circular columns 6.
The minimum diameter of longitudinal bars in a column is:
- 12 mm
- 8 mm
- 10 mm
- 16 mm
Answer
A. 12 mm
IS 456 specifies 12 mm.
The minimum diameter of lateral ties for columns with 16 mm longitudinal bars is:
- 8 mm
- 6 mm
- 4 mm
- 10 mm
Answer
B. 6 mm
Larger of 16/4 = 4 mm and 6 mm, so 6 mm.
A 250 mm × 400 mm column has 16 mm longitudinal bars. The maximum pitch of lateral ties is:
- 256 mm
- 300 mm
- 400 mm
- 250 mm
Answer
D. 250 mm
Least of 250 (least dimension), 16 × 16 = 256 and 300 is 250 mm.
Compared with a tied column, the strength of a helically reinforced column is taken as:
- 1.05 times
- Equal
- 1.5 times
- 1.25 times
Answer
A. 1.05 times
IS 456 allows 5% higher strength for helical reinforcement if conditions are met.
The maximum pitch of helical reinforcement in a column is:
- 75 mm or one-sixth of core diameter, whichever is less
- 25 mm
- 150 mm
- 300 mm only
Answer
A. 75 mm or one-sixth of core diameter, whichever is less
Pitch should not exceed 75 mm and core diameter/6.
For a column of 6 m effective length, D = 400 mm and Pu = 1000 kN, the additional moment Ma = (Pu D/2000)(le/D)² is:
- 22.5 kN·m
- 90 kN·m
- 45 kN·m
- 15 kN·m
Answer
C. 45 kN·m
le/D = 15; Ma = 0.2 × 225 = 45 kN·m.
The effective length of a column with both ends fixed (theoretical) is:
- 1.0 L
- 0.65 L
- 0.8 L
- 0.5 L
Answer
B. 0.65 L
Fixed-fixed ends give 0.65 L.
The effective length of a column fixed at one end and free at the other is:
- 0.8 L
- 1.0 L
- 1.5 L
- 2.0 L
Answer
D. 2.0 L
A cantilever column buckles with an effective length of twice its height.
The effective length of a column hinged at both ends is:
- 0.65 L
- 1.0 L
- 0.8 L
- 2.0 L
Answer
B. 1.0 L
Both ends hinged and not sway: le = L.
The normal nominal cover to the main bars of a column is:
- 25 mm
- 75 mm
- 40 mm
- 20 mm
Answer
C. 40 mm
IS 456 specifies 40 mm or the bar diameter, whichever is greater.
The minimum cover to the reinforcement at the earth face of a footing is:
- 75 mm
- 50 mm
- 25 mm
- 30 mm
Answer
B. 50 mm
Footing steel in contact with earth gets a minimum cover of 50 mm.
A column carries 900 kN. The safe bearing capacity is 150 kN/m² and 10% extra is added for footing weight. The footing area is:
- 6.6 m²
- 7.2 m²
- 6.0 m²
- 5.4 m²
Answer
A. 6.6 m²
A = 1.1 × 900/150 = 6.6 m².
The critical section for one-way shear in an isolated footing is at a distance from the column face of:
- d/2
- 2d
- Zero
- d
Answer
D. d
Beam-type shear is checked at d from the column face.
The permissible punching shear stress τc for M20 concrete and a square column is nearly (τc' = 0.25√fck):
- 1.5 N/mm²
- 0.56 N/mm²
- 1.12 N/mm²
- 2.0 N/mm²
Answer
C. 1.12 N/mm²
0.25 × √20 = 1.118 N/mm² (ks = 1 for square column).
The critical section for bending moment in an isolated footing is at:
- Distance d/2 from the column face
- The face of the column
- Distance d from the column face
- Centre of the footing
Answer
B. The face of the column
Moment is calculated at the column face.
A 2 m × 2 m footing carries 600 kN with eccentricity 0.2 m in one direction. The maximum soil pressure is:
- 240 kN/m²
- 180 kN/m²
- 300 kN/m²
- 150 kN/m²
Answer
A. 240 kN/m²
p = (600/4)(1 + 6 × 0.2/2) = 150 × 1.6 = 240 kN/m².
For a combined footing under two columns of 600 kN and 400 kN spaced 4 m apart, the resultant load is at what distance from the 600 kN column?
- 2.0 m
- 1.0 m
- 1.6 m
- 2.4 m
Answer
C. 1.6 m
Moment about 600 kN column: 400 × 4/1000 = 1.6 m.
The minimum thickness at the edge of a footing resting on soil is:
- 200 mm
- 100 mm
- 300 mm
- 150 mm
Answer
D. 150 mm
IS 456: 150 mm on soil and 300 mm on piles.
In bearing at a column base the limit on √(A1/A2) is:
- 1
- 2
- 3
- 4
Answer
B. 2
Allowable bearing stress is 0.45 fck √(A1/A2) with √(A1/A2) ≤ 2.
The minimum area of dowel bars across a column-footing junction is:
- 0.15% of the footing area
- 0.8% of the column cross-section
- 1% of the footing area
- 0.5% of the column cross-section
Answer
D. 0.5% of the column cross-section
IS 456 requires dowels of not less than 0.5% of the supported column area.
Which of the following statements are correct? 1. Slabs normally do not need shear reinforcement. 2. The minimum steel percentage in a slab depends on the steel grade.
- 1 only
- 2 only
- Both 1 and 2
- Neither 1 nor 2
Answer
C. Both 1 and 2
Both are true: τv is usually less than τc and minimum steel is 0.15% for Fe 250 and 0.12% for Fe 415.
Which of the following statements are correct? 1. Short columns fail mainly by crushing. 2. Slender columns fail mainly by buckling.
- 1 only
- 2 only
- Both 1 and 2
- Neither 1 nor 2
Answer
C. Both 1 and 2
Short columns crush; long columns buckle and need an additional moment.
Which of the following statements are correct? 1. A pedestal has height not exceeding three times its least lateral dimension. 2. A pedestal must always carry at least 0.8% longitudinal steel.
- 1 only
- 2 only
- Both 1 and 2
- Neither 1 nor 2
Answer
A. 1 only
Statement 2 is false: it is the column rule; pedestals are generally plain.
A footing used when one column lies close to the property line and its footing cannot be centred is a:
- Isolated square footing
- Circular footing
- Pedestal footing
- Strap (cantilever) footing
Answer
D. Strap (cantilever) footing
A strap beam joins the eccentric footing to an interior footing to balance the moment.
Which statement about footing design is correct?
- Both size and thickness use factored loads
- Both use working loads
- Size is found from working loads; thickness is designed using factored loads
- Self weight is added in bending design
Answer
C. Size is found from working loads; thickness is designed using factored loads
Soil pressure is checked at working load while shear and bending use factored net pressure.
Which is NOT an advantage of a flat slab compared with a beam-slab floor?
- Greater resistance to lateral loads
- Simple formwork
- Flat soffit
- More headroom
Answer
A. Greater resistance to lateral loads
Flat slabs lack beams and resist lateral loads poorly.
In two-way slabs with ly/lx ≤ 2, the larger moment occurs per metre width in the:
- Longer span direction
- Diagonal direction only
- Both equal in all cases
- Shorter span direction
Answer
D. Shorter span direction
The stiffer short direction carries more load, giving the larger moment coefficient.