Machine Tools, Metrology, Production and Operations Management
What to remember
- Cutting speed V = πDN/1000 (m/min). Tool life follows Taylor's equation V Tⁿ = C. Material removal rate in turning = V × f × d (speed × feed × depth of cut, in consistent units).
- Metrology rests on accuracy, least count, limits and fits (hole basis), Taylor's principle of gauging (GO gauge checks full form, NO-GO checks one dimension) and standard tools like micrometer, vernier, slip gauges and sine bar.
- Operations management gives formulas: EOQ = √(2DS/H), PERT time = (a + 4m + b)/6, Cp = (USL - LSL)/6σ, break-even = F/(p - v), line balancing cycle time = available time/demand.
1. Machine tools and cutting basics
Lathe operations: turning, facing, taper turning, threading, drilling, boring, knurling, parting.
- Cutting speed V = π D N / 1000 m/min (D in mm, N in rpm).
- Machining time for turning: T = L / (f N) minutes, where L is the length of cut and f is feed per revolution.
- Material removal rate in turning: MRR = V f d (V in mm/min if f and d are in mm).
- Taper turning: tailstock offset = (D - d) L / (2 l), where D and d are the large and small diameters of the taper, l is the length of the taper and L is the length of the job. Compound rest is set at half the taper angle: tan α = (D - d) / (2 l).
- Drilling: twist drill, point angle about 118°. Milling: peripheral (slab) and face milling; up milling (conventional, cutter rotation opposes feed) and down milling (climb milling, cutter rotation with feed; better surface and needs backlash eliminator).
- Simple indexing in a dividing head: index crank turns = 40 / N for N divisions (worm gear ratio 40:1).
- Shaper uses a quick-return mechanism: the cutting stroke is slower than the return stroke. Planer: the work table moves and the tool is stationary. Slotter: vertical shaper. Broaching: a multi-tooth tool pushed or pulled through the workpiece.
- Grinding: abrasives aluminium oxide (steel) and silicon carbide (cast iron, non-ferrous). Glazing: wheel becomes dull. Loading: chips clog the wheel. Dressing restores the wheel.
- CNC (computer numerical control): G00 rapid positioning, G01 linear interpolation, G02 circular interpolation clockwise, G03 anticlockwise, M03 spindle clockwise, M05 spindle stop, M30 program end. CNC gives high accuracy and repeatability.
- Non-traditional machining: EDM (spark erosion in dielectric fluid; works on any conductive material), ECM (electrochemical, no tool wear), USM (ultrasonic, for brittle materials), AJM, LBM, plasma arc machining.
2. Mechanics of metal cutting
- Orthogonal cutting: the cutting edge is perpendicular to the cutting speed. Chip thickness ratio r = t / tc = (uncut thickness / chip thickness), always less than 1.
- Shear angle: tan φ = r cos α / (1 - r sin α), where α is the rake angle.
- Merchant's relation: φ = 45° + α/2 - β/2, where β is the friction angle.
- Chip types: continuous (ductile metals, high speed), discontinuous (brittle metals), built-up edge (BUE, low speed on ductile metals; poor finish).
- Tool signature (ASA): back rake, side rake, end relief, side relief, end cutting edge angle, side cutting edge angle, nose radius.
- Tool materials: high speed steel (18% W, 4% Cr, 1% V), cemented carbide (tungsten carbide with cobalt binder), ceramics, cubic boron nitride and diamond. Hot hardness rises from HSS to carbide to ceramic.
- Taylor's tool life equation: V Tⁿ = C. Typical n: about 0.1 to 0.2 for HSS, 0.2 to 0.4 for carbide, 0.4 to 0.6 for ceramic. Tool life drops quickly as speed increases.
- Cutting fluids cool and lubricate and wash away chips.
- Most of the energy in cutting becomes heat: major share is carried away in the chip.
Worked example. Taylor's n = 0.25 and tool life 60 min at 100 m/min. At 50 m/min the life becomes 60 × 2⁴ = 960 min (T is proportional to V^(-1/n)).
3. Metrology
- Accuracy: closeness to the true value. Precision: repeatability. Least count: smallest reading of the instrument. Sensitivity: change in output per change in measured value.
- Vernier caliper: least count = 1 MSD - 1 VSD. Micrometer: least count = pitch / number of thimble divisions; 0.5 mm / 50 = 0.01 mm.
- Limits, fits and tolerances: basic size, upper and lower deviation, tolerance = upper limit - lower limit. Types of fit: clearance (shaft always smaller than hole), interference (shaft always larger), transition (either). Hole basis system: hole has zero lower deviation (H); more common because holes are made with standard tools. Shaft basis: shaft has zero upper deviation (h). Standard tolerance grades IT01 to IT18.
- Gauging: the GO gauge checks the maximum material limit and has full form; the NO-GO gauge checks the least material limit and checks one dimension at a time (Taylor's principle). Plug gauges check holes; ring and snap gauges check shafts.
- Slip gauges (gauge blocks): very flat blocks that wring together to make any size; used for calibration.
- Sine bar: sin θ = h / L, where h is the height of the slip gauge stack under one roller and L is the distance between roller centres. It is not suitable beyond about 45° because of error growth. For L = 200 mm and θ = 30°, h = 100 mm.
- Comparators: mechanical (dial gauge), optical, pneumatic (air gauging) and electrical. They compare a part with a standard.
- Optical flat and interference: each fringe represents a height difference of λ/2. Autocollimator measures small angles and straightness. Bevel protractor measures angles. Screw threads: three-wire method for effective diameter. Profile projector for contours. CMM (coordinate measuring machine) measures 3D coordinates.
- Surface roughness: Ra (arithmetic average) and Rz (mean peak to valley height). Abbe's principle: the measuring axis should be in line with the axis of the scale. Calibration compares an instrument against a higher standard.
4. Production and operations management
Forecasting: moving average, exponential smoothing: F(t+1) = α A(t) + (1 - α) F(t), where α is the smoothing constant (0 to 1). Mean absolute deviation (MAD) measures forecast error. Delphi is a qualitative method.
Inventory control:
- Economic order quantity EOQ = √(2 D S / H), where D = annual demand, S = ordering cost per order, H = holding cost per unit per year. At EOQ, the annual ordering cost equals the annual holding cost.
- Reorder point = demand during lead time + safety stock.
- ABC analysis: A items are few but of high value (about 70% of value from 10% of items); C items are many with low value. VED: vital, essential, desirable. FSN: fast, slow, non-moving.
- Example: D = 1000 units, S = 50, H = 10 per unit/year: EOQ = √(2 × 1000 × 50 / 10) = 100 units.
- In power plants, spare parts of high value, like turbine blades, are placed under tight control (A class), while nuts and bolts are C class.
Production systems and planning: job, batch, mass and continuous production. Layouts: product (line), process (functional), fixed position, cellular (group technology). MRP uses bill of materials, inventory status and master production schedule. JIT and Kanban (Toyota) aim to remove waste (lean). Productivity = output / input.
Line balancing: cycle time = available time / required output. Minimum number of workstations = (sum of task times) / cycle time, rounded up. Line efficiency = sum of task times / (number of stations × cycle time).
Work study: method study (improve methods) and work measurement (time study, work sampling). Normal time = observed time × rating factor. Standard time = normal time × (1 + allowance fraction).
Project management: CPM uses fixed times; PERT uses three estimates: optimistic a, most likely m, pessimistic b.
- Expected time te = (a + 4m + b)/6; variance = ((b - a)/6)².
- Critical path = longest path; activities on it have zero total float. Total float = LST - EST (or LFT - EFT).
- A Gantt chart shows activities against time.
Scheduling and others: Johnson's rule gives the optimal sequence for n jobs on two machines. Shortest processing time (SPT) rule minimises average flow time. Assignment problems use the Hungarian method; transportation problems use the north-west corner, least cost and Vogel's approximation methods.
Quality: control charts: X-bar and R charts for variables; p and c charts for attributes. Process capability Cp = (USL - LSL) / 6σ; Cp of 1.33 or more is considered capable. Six Sigma targets 3.4 defects per million opportunities. TQM, ISO 9000 and Pareto analysis support quality improvement.
Break-even analysis: BEP quantity = fixed cost / (selling price per unit - variable cost per unit).
Maintenance: breakdown, preventive, predictive and total productive maintenance (TPM). Overhauls of power plant units are usually planned with CPM networks.
Exam traps
- Cutting speed uses diameter in mm and gives m/min; feed is per revolution in turning.
- Chip thickness ratio is below 1, because the chip is thicker than the uncut layer.
- Go gauge checks maximum material and full form; no-go checks one dimension.
- Hole basis: hole lower deviation is zero; shaft basis: shaft upper deviation is zero.
- Precision is not accuracy.
- EOQ: the holding cost H is per unit per year, not total.
- PERT time has a factor 4 on the most likely time.
- Critical path is the longest path, not the shortest.
One-liners
- 1. Cutting speed V = π D N / 1000.
- 2. Taylor's equation: V Tⁿ = C.
- 3. Carbide tools allow higher cutting speeds than HSS.
- 4. Up milling is conventional milling; down milling is climb milling.
- 5. Simple indexing uses 40/N turns of the crank.
- 6. A micrometer with 0.5 mm pitch and 50 divisions has least count 0.01 mm.
- 7. Sine bar relation: sin θ = h / L.
- 8. G01 means linear interpolation in CNC.
- 9. EOQ balances ordering cost and holding cost.
- 10. PERT expected time = (a + 4m + b)/6.
- 11. ABC analysis classifies items by value.
- 12. Six Sigma allows 3.4 defects per million opportunities.
Practice questions
The cutting speed in turning, in m/min, is given by (D in mm, N in rpm)
- π D N
- π D N / 1000
- π D² N / 1000
- D N / 1000
Answer
B. π D N / 1000
V = π D N / 1000 converts mm/min to m/min.
A job of 100 mm diameter is turned at 300 rpm. The cutting speed is about
- 94 m/min
- 9.4 m/min
- 30 m/min
- 300 m/min
Answer
A. 94 m/min
V = π × 100 × 300 / 1000 = 94.2 m/min.
A 300 mm long cut is made at feed 0.5 mm/rev and 300 rpm. The machining time is
- 4 min
- 0.5 min
- 2 min
- 1 min
Answer
C. 2 min
T = L / (f N) = 300 / (0.5 × 300) = 2 min.
At cutting speed 100 m/min, feed 0.2 mm/rev and depth of cut 2 mm, the material removal rate is
- 400 mm³/min
- 40,000 mm³/min
- 20,000 mm³/min
- 4000 mm³/min
Answer
B. 40,000 mm³/min
MRR = V f d = 100,000 × 0.2 × 2 = 40,000 mm³/min.
In Taylor's tool life equation V Tⁿ = C, the constant n is largest for
- High speed steel tools
- All tools equally
- Carbon tool steel
- Ceramic tools
Answer
D. Ceramic tools
n is about 0.1-0.2 for HSS, 0.2-0.4 for carbide and 0.4-0.6 for ceramics.
For Taylor's n = 0.25, if the cutting speed is halved, the tool life becomes
- 8 times
- 2 times
- 16 times
- 4 times
Answer
C. 16 times
T is proportional to V^(-1/n) = V⁻⁴; halving V gives 2⁴ = 16.
Chip thickness ratio r = t / tc in orthogonal cutting is generally
- Less than 1
- Greater than 1
- Exactly 1
- Equal to the shear angle
Answer
A. Less than 1
The chip is thicker than the uncut layer.
In orthogonal cutting the uncut thickness is 0.2 mm and the chip thickness is 0.4 mm. The chip thickness ratio is
- 2
- 0.2
- 0.5
- 0.8
Answer
C. 0.5
r = t / tc = 0.2 / 0.4.
Merchant's relation gives the shear angle φ as
- 45° - α/2 + β/2
- 90° - α - β
- 45° + α + β
- 45° + α/2 - β/2
Answer
D. 45° + α/2 - β/2
α is the rake angle and β is the friction angle.
With rake angle 10° and friction angle 30°, the shear angle from Merchant's relation is
- 55°
- 35°
- 25°
- 45°
Answer
B. 35°
φ = 45 + 5 - 15 = 35°.
Tailstock offset for turning a taper: total length of job 400 mm, taper length 200 mm, diameters 60 mm and 40 mm. The offset is
- 5 mm
- 10 mm
- 40 mm
- 20 mm
Answer
D. 20 mm
Offset = (D - d) L / (2 l) = 20 × 400 / 400 = 20 mm.
To mill 8 equal divisions using simple indexing, the index crank is turned by
- 8 turns
- 5 turns
- 40 turns
- 0.2 turn
Answer
B. 5 turns
Turns = 40 / N = 40 / 8 = 5.
In climb (down) milling
- The cutter rotation is in the direction of feed at cut entry
- The work is clamped loosely
- The cutter rotation opposes the feed
- The chip thickness is zero at start always
Answer
A. The cutter rotation is in the direction of feed at cut entry
It gives better surface but needs a backlash eliminator.
A quick-return mechanism is used in a
- Shaper
- Drilling machine
- Lathe
- Grinder
Answer
A. Shaper
The return stroke is faster than the cutting stroke.
In CNC programming G01 means
- Spindle stop
- Circular interpolation clockwise
- Linear interpolation
- Rapid positioning
Answer
C. Linear interpolation
G00 is rapid positioning; G02 is clockwise arc; M05 stops the spindle.
Electrical discharge machining (EDM) can machine materials that are
- Electrically conductive
- Only brittle non-metals
- Only soft plastics
- Only ceramics
Answer
A. Electrically conductive
Spark erosion needs a conductive workpiece in a dielectric fluid.
The least count of a micrometer with pitch 0.5 mm and 50 thimble divisions is
- 0.02 mm
- 0.1 mm
- 0.05 mm
- 0.01 mm
Answer
D. 0.01 mm
LC = pitch / divisions = 0.5 / 50.
A vernier has 10 divisions equal to 9 main scale divisions of 1 mm each. The least count is
- 0.01 mm
- 0.1 mm
- 0.9 mm
- 1 mm
Answer
B. 0.1 mm
LC = 1 MSD - 1 VSD = 1 - 0.9 = 0.1 mm.
Repeatability of measurement is called
- Sensitivity
- Accuracy
- Range
- Precision
Answer
D. Precision
Accuracy is closeness to the true value.
In the hole basis system, the hole has
- Zero upper deviation
- Zero lower deviation
- Negative tolerance only
- Maximum interference
Answer
B. Zero lower deviation
Hole is designated H; shaft deviations vary to give the fit.
Hole: 50.00 to 50.05 mm; shaft: 49.90 to 49.95 mm. The minimum clearance is
- 0.10 mm
- 0.15 mm
- 0.05 mm
- 0
Answer
C. 0.05 mm
Min clearance = hole min - shaft max = 50.00 - 49.95 = 0.05 mm.
According to Taylor's principle, the GO gauge
- Checks the maximum material limit with full form
- Checks the least material limit
- Checks only one dimension
- Is always the shorter gauge
Answer
A. Checks the maximum material limit with full form
The NO-GO gauge checks the least material limit, one dimension at a time.
A sine bar of centre distance 100 mm is set to 30°. The height of the slip gauge stack is
- 30 mm
- 100 mm
- 50 mm
- 86.6 mm
Answer
C. 50 mm
h = L sin θ = 100 × 0.5.
Each interference fringe seen with an optical flat shows a height difference of
- λ / 4
- λ
- 2λ
- λ / 2
Answer
D. λ / 2
Light travels the gap twice, so a fringe represents half a wavelength.
Ten fringes are seen with light of wavelength 0.6 μm. The height difference is
- 6 μm
- 3 μm
- 1.2 μm
- 0.3 μm
Answer
B. 3 μm
Height = 10 × λ/2 = 10 × 0.3 = 3 μm.
Economic order quantity is given by
- √(2 H / D S)
- 2 D S / H
- √(2 D S / H)
- √(D S / 2H)
Answer
C. √(2 D S / H)
D = annual demand, S = ordering cost per order, H = holding cost per unit per year.
Annual demand 800 units, ordering cost 25 per order, holding cost 4 per unit per year. The EOQ is
- 200 units
- 50 units
- 400 units
- 100 units
Answer
D. 100 units
EOQ = √(2 × 800 × 25 / 4) = √10,000 = 100.
At the economic order quantity
- Ordering cost equals holding cost
- Holding cost is zero
- Total cost is maximum
- Ordering cost is zero
Answer
A. Ordering cost equals holding cost
Total cost is minimum where the two annual costs are equal.
In ABC analysis, class A items are
- Many in number and low in value
- Non-moving items
- Only perishable items
- Few in number but high in value
Answer
D. Few in number but high in value
A items need tight control.
Using exponential smoothing with α = 0.2, last actual 100 and last forecast 80, the next forecast is
- 80
- 84
- 88
- 90
Answer
B. 84
F = 0.2 × 100 + 0.8 × 80 = 20 + 64 = 84.
PERT optimistic, most likely and pessimistic times are 2, 5 and 14 days. The expected time is
- 6 days
- 8 days
- 5 days
- 7 days
Answer
A. 6 days
te = (2 + 4 × 5 + 14) / 6 = 36/6.
For the same activity (a = 2, b = 14), the variance is
- 4
- 2
- 12
- 36
Answer
A. 4
((b - a)/6)² = (12/6)² = 4.
The critical path in a network is
- The shortest path
- The path with most activities
- The longest path
- The path with the largest float
Answer
C. The longest path
It determines the project duration; its activities have zero total float.
Total task time on an assembly line is 120 s and the cycle time is 30 s. The minimum number of workstations is
- 3
- 5
- 6
- 4
Answer
D. 4
N = 120 / 30 = 4.
With 5 stations and cycle time 30 s, total task time of 120 s gives a line efficiency of
- 100%
- 80%
- 60%
- 96%
Answer
B. 80%
Efficiency = 120 / (5 × 30) = 0.8.
Observed time 2 min, rating factor 110% and allowance 10% of normal time. The standard time is
- 2.0 min
- 2.62 min
- 2.42 min
- 2.2 min
Answer
C. 2.42 min
Normal = 2 × 1.1 = 2.2; standard = 2.2 × 1.1 = 2.42 min.
Fixed cost 60,000, selling price 50 and variable cost 30 per unit. The break-even quantity is
- 6000 units
- 3000 units
- 2000 units
- 1200 units
Answer
B. 3000 units
BEP = 60,000 / (50 - 30) = 3000.
A process has USL - LSL = 12 and σ = 1.5. Cp is
- 8
- 1.33
- 0.8
- 0.67
Answer
B. 1.33
Cp = 12 / (6 × 1.5) = 1.33.
An activity has earliest start 3 days and latest start 7 days. Its total float is
- 4 days
- 3 days
- 0
- 10 days
Answer
A. 4 days
Float = LST - EST = 7 - 3.
Consider: 1. CPM uses three time estimates for each activity. 2. In a network, the critical path is the longest path. Which is/are correct?
- 1 only
- 2 only
- Both 1 and 2
- Neither 1 nor 2
Answer
B. 2 only
CPM uses one time; PERT uses three estimates. So 1 is wrong.
Johnson's rule is used to find the optimal sequence for
- Transportation costs
- Inventory levels
- One job on n machines
- n jobs on two machines
Answer
D. n jobs on two machines
It minimises total makespan on two machines in series.
Consider: 1. Precision means closeness to the true value. 2. Least count is the smallest reading an instrument can give. Which is/are correct?
- 1 only
- 2 only
- Both 1 and 2
- Neither 1 nor 2
Answer
B. 2 only
Precision is repeatability, not closeness to the true value (accuracy), so 1 is wrong.
Six Sigma quality aims at about
- 34 defects per million
- 3400 defects per million
- 3.4 defects per million opportunities
- 0.34 defects per million
Answer
C. 3.4 defects per million opportunities
This is the standard Six Sigma target.
Consider: 1. In turning, the feed is expressed per revolution. 2. In the hole basis system the hole is designated H. Which is/are correct?
- 1 only
- 2 only
- Both 1 and 2
- Neither 1 nor 2
Answer
C. Both 1 and 2
Both statements are correct.
Which gauge is generally used to check a hole of fixed size?
- Plug gauge
- Sine bar
- Snap gauge
- Ring gauge
Answer
A. Plug gauge
Plug gauges check holes; ring and snap gauges check shafts.