Mensuration: 2D and 3D
What to remember
- Mensuration measures lengths, areas and volumes. Area is in square units, volume in cubic units, and 1 m³ = 1000 litres. Use π = 22/7 unless told otherwise.
- Learn the 2D formulas for the triangle, rectangle, parallelogram, rhombus, trapezium, circle and sector, and the 3D formulas for the cube, cuboid, cylinder, cone, sphere and hemisphere.
- When a solid is melted and recast, the volume stays the same. Use volume equality to count the new pieces.
Plane figures: area and perimeter
| Figure | Area | Perimeter |
|---|---|---|
| Rectangle (l, b) | l × b | 2(l + b) |
| Square (a) | a² = d²/2 (d = diagonal) | 4a |
| Triangle | ½ × base × height | sum of sides |
| Equilateral triangle (a) | (√3/4) a² | 3a |
| Heron's formula (sides a, b, c, s = half the perimeter) | √[s(s − a)(s − b)(s − c)] | a + b + c |
| Parallelogram | base × height | 2(sum of adjacent sides) |
| Rhombus | ½ × d₁ × d₂ | 4 × side |
| Trapezium | ½ × (sum of parallel sides) × height | sum of sides |
Worked examples.
- A rectangle 12 × 5 has area 60. A square of area 144 has side 12 and perimeter 48.
- A triangle with base 10 and height 7 has area 35.
- Sides 13, 14, 15: s = 21, area = √(21 × 8 × 7 × 6) = √7056 = 84.
- An equilateral triangle of side 8 has area (√3/4) × 64 = 16√3.
- A rhombus with diagonals 10 and 24 has area 120. A trapezium with parallel sides 9 and 15 and height 8 has area 96.
- A parallelogram with base 12 and height 7 has area 84.
- A rectangle with perimeter 30 and length 9 has breadth 6 and area 54. A square with diagonal 12 has area 72.
- A park 20 × 15 with a 2 m path all round outside: outer rectangle 24 × 19 = 456, so path area = 456 − 300 = 156.
Circle, sector and ring
| Quantity | Formula (radius r, angle θ at centre) |
|---|---|
| Circumference | 2πr |
| Area | πr² |
| Arc length | (θ/360°) × 2πr |
| Area of sector | (θ/360°) × πr² |
| Area of ring (outer R, inner r) | π(R² − r²) |
| Perimeter of semicircle | πr + 2r |
Worked examples.
- r = 7: area = 22/7 × 49 = 154. r = 14: circumference = 2 × 22/7 × 14 = 88.
- Sector of angle 60° and r = 21: area = 1/6 × 22/7 × 441 = 231. Arc length = 1/6 × 2 × 22/7 × 21 = 22.
- Ring with R = 14 and r = 7: area = 22/7 × (196 − 49) = 462.
- A wire of length 44 bent into a circle has 2πr = 44, so r = 7 and area 154.
- A semicircle of radius 7 has perimeter 22 + 14 = 36.
Scaling. If the radius of a circle increases by 10%, the area becomes (1.1)² = 1.21 times, an increase of 21%.
Solids: surface area and volume
| Solid | Volume | Curved surface area (CSA) | Total surface area (TSA) |
|---|---|---|---|
| Cube (a) | a³ | 4a² (four walls) | 6a² |
| Cuboid (l, b, h) | lbh | 2h(l + b) | 2(lb + bh + hl) |
| Cylinder (r, h) | πr²h | 2πrh | 2πr(r + h) |
| Cone (r, h, slant l) | ⅓πr²h | πrl | πr(r + l) |
| Sphere (r) | (4/3)πr³ | 4πr² | 4πr² |
| Hemisphere (r) | (2/3)πr³ | 2πr² | 3πr² |
| Prism | base area × height | perimeter of base × height | CSA + 2 × base area |
Other relations:
- Cone: l² = r² + h². Cube diagonal = a√3. Cuboid diagonal = √(l² + b² + h²).
- Frustum of a cone (radii R and r, height h): volume = (πh/3)(R² + Rr + r²).
Worked examples.
- Cube a = 5: volume 125, TSA 150, diagonal 5√3.
- Cuboid 8 × 6 × 5: volume 240, TSA 2(48 + 30 + 40) = 236. A cuboid 4 × 3 × 12 has diagonal √(16 + 9 + 144) = 13.
- Cylinder r = 7, h = 10: volume = 22/7 × 49 × 10 = 1540, CSA = 2 × 22/7 × 7 × 10 = 440.
- Cone r = 7, h = 24: slant = √(49 + 576) = 25, volume = ⅓ × 22/7 × 49 × 24 = 1232, CSA = 22/7 × 7 × 25 = 550.
- Sphere r = 7: surface area = 4 × 22/7 × 49 = 616. Sphere r = 21: volume = 4/3 × 22/7 × 9261 = 38808.
- Hemisphere r = 7: CSA = 308, TSA = 462.
- A triangular prism with base 6, height 4 and length 10: volume = 12 × 10 = 120.
- A tank 5 m × 4 m × 3 m holds 60 m³ = 60,000 litres.
Change of shape and ratios
Melting and recasting. Volume before = volume after. A sphere of radius 6 recast into small spheres of radius 2 gives (6/2)³ = 27 spheres. A wire drawn from a metal block has volume πr²h.
Scaling rules.
- If every linear dimension is multiplied by k, area becomes k² times and volume k³ times. Doubling a cube's edge makes the surface area 4 times and the volume 8 times.
- Cylinders of equal height with radii in the ratio 2 : 3 have volumes in the ratio 4 : 9.
- A cone and a cylinder with the same base and height have volumes in the ratio 1 : 3.
Units. 1 m = 100 cm, so 1 m² = 10,000 cm² and 1 m³ = 10⁶ cm³. 1 litre = 1000 cm³ and 1 m³ = 1000 litres.
For forestry-type problems, treat a log as a cylinder and a stack of wood as a cuboid. Use cross-section area × length for volume.
Practical mensuration for forestry-type problems
- Log or pole. A log is a cylinder. A log of radius 0.35 m and length 10 m has volume (22/7) × 0.35 × 0.35 × 10 = 3.85 m³. Always use the same unit for radius and length.
- Timber stack. A rectangular stack of wood is a cuboid. Its volume is length × breadth × height. A stack 6 m × 2 m × 1.5 m holds 18 m³.
- Water tank or trench. A trench is a cuboid, a circular well is a cylinder. Digging a well of radius r and depth h removes πr²h of soil, which spread over a rectangular field raises it by (volume) / (area of field).
- Tree trunk cone. The cone formula is used for tent-shaped heaps. A heap of grain in the form of a cone with radius 7 m and height 3 m has volume ⅓ × 22/7 × 49 × 3 = 154 m³.
- Fencing and planting. The perimeter gives the length of fence needed. The area divided by the area per plant gives the number of plants. A rectangular plot 50 m × 30 m with one plant per 5 m² has 1500 / 5 = 300 plants.
- Combination of solids. A solid made of a cylinder with a hemisphere on top has volume πr²h + (2/3)πr³ and surface area 2πrh + 2πr² + πr² (curved surface of the cylinder, hemisphere and the base).
Conversions and common slips
| Quantity | Conversion |
|---|---|
| 1 hectare | 10,000 m² |
| 1 km² | 100 hectares |
| 1 m² | 10,000 cm² |
| 1 litre | 1000 cm³ |
| 1 m³ | 1000 litres |
Always check that all lengths use the same unit before substituting into a formula. For a closed cylinder the total surface area is the curved surface plus the two circular ends, 2πr(r + h).
Exam traps
- Using the radius when the diameter is given, or the other way round.
- Using the height h instead of the slant height l in the CSA of a cone.
- Forgetting the ⅓ in the volume of a cone, or the 4/3 in the volume of a sphere.
- Confusing CSA with TSA. TSA includes the circular ends (and for a hemisphere, the flat top).
- Using the slant side instead of the perpendicular height in the area of a parallelogram or trapezium.
- Leaving out the square when the radius changes by a percentage (area changes as r²).
- Forgetting to convert units (cm to m, or m³ to litres) before the final answer.
- Applying k² for volume. Volume scales as k³; only area scales as k².
One-liners
- 1. Area of a triangle = ½ × base × height.
- 2. Heron's formula: area = √[s(s − a)(s − b)(s − c)].
- 3. Area of an equilateral triangle = (√3/4) a².
- 4. Area of a rhombus = ½ × d₁ × d₂.
- 5. Area of a trapezium = ½ × (a + b) × h.
- 6. Area of a circle = πr²; circumference = 2πr.
- 7. Volume of a cylinder = πr²h; CSA = 2πrh.
- 8. Volume of a cone = ⅓πr²h; slant height l = √(r² + h²).
- 9. Volume of a sphere = (4/3)πr³; surface area = 4πr².
- 10. TSA of a hemisphere = 3πr².
- 11. Volume of a cube = a³; TSA = 6a².
- 12. 1 m³ = 1000 litres.
Practice questions
The area of a triangle with base 10 cm and height 7 cm is
- 24.5 cm²
- 17 cm²
- 35 cm²
- 70 cm²
Answer
C. 35 cm²
½ × 10 × 7 = 35.
The perimeter of a square whose area is 144 cm² is
- 36 cm
- 12 cm
- 144 cm
- 48 cm
Answer
D. 48 cm
Side = 12, perimeter = 4 × 12 = 48.
The area of a triangle with sides 13 cm, 14 cm and 15 cm is
- 91 cm²
- 42 cm²
- 105 cm²
- 84 cm²
Answer
D. 84 cm²
s = 21; √(21 × 8 × 7 × 6) = 84.
The area of an equilateral triangle of side 8 cm is
- 8√3 cm²
- 16√3 cm²
- 64√3 cm²
- 32√3 cm²
Answer
B. 16√3 cm²
(√3/4) × 64 = 16√3.
The area of a circle of radius 7 cm (π = 22/7) is
- 154 cm²
- 308 cm²
- 44 cm²
- 49 cm²
Answer
A. 154 cm²
22/7 × 49 = 154.
The circumference of a circle of radius 14 cm (π = 22/7) is
- 616 cm
- 44 cm
- 88 cm
- 154 cm
Answer
C. 88 cm
2 × 22/7 × 14 = 88.
The area of a rhombus with diagonals 10 cm and 24 cm is
- 120 cm²
- 34 cm²
- 130 cm²
- 240 cm²
Answer
A. 120 cm²
½ × 10 × 24 = 120.
The area of a trapezium with parallel sides 9 cm and 15 cm and height 8 cm is
- 72 cm²
- 96 cm²
- 192 cm²
- 120 cm²
Answer
B. 96 cm²
½ × (9 + 15) × 8 = 96.
The area of a sector of angle 60° in a circle of radius 21 cm (π = 22/7) is
- 1386 cm²
- 22 cm²
- 462 cm²
- 231 cm²
Answer
D. 231 cm²
1/6 × 22/7 × 441 = 231.
The length of an arc of angle 60° in a circle of radius 21 cm (π = 22/7) is
- 11 cm
- 44 cm
- 22 cm
- 132 cm
Answer
C. 22 cm
1/6 × 2 × 22/7 × 21 = 22.
The area of a ring with outer radius 14 cm and inner radius 7 cm (π = 22/7) is
- 462 cm²
- 154 cm²
- 308 cm²
- 616 cm²
Answer
A. 462 cm²
22/7 × (196 − 49) = 462.
The volume of a cube of edge 5 cm is
- 150 cm³
- 125 cm³
- 75 cm³
- 25 cm³
Answer
B. 125 cm³
5³ = 125.
The total surface area of a cube of edge 5 cm is
- 125 cm²
- 100 cm²
- 150 cm²
- 30 cm²
Answer
C. 150 cm²
6 × 25 = 150.
The diagonal of a cuboid 4 cm × 3 cm × 12 cm is
- 19 cm
- 12.5 cm
- 5 cm
- 13 cm
Answer
D. 13 cm
√(16 + 9 + 144) = √169 = 13.
The volume of a cylinder of radius 7 cm and height 10 cm (π = 22/7) is
- 154 cm³
- 1540 cm³
- 4620 cm³
- 440 cm³
Answer
B. 1540 cm³
22/7 × 49 × 10 = 1540.
The curved surface area of a cylinder of radius 7 cm and height 10 cm (π = 22/7) is
- 440 cm²
- 1540 cm²
- 308 cm²
- 880 cm²
Answer
A. 440 cm²
2 × 22/7 × 7 × 10 = 440.
A cone has radius 7 cm and height 24 cm. Its slant height is
- 23 cm
- 17 cm
- 31 cm
- 25 cm
Answer
D. 25 cm
√(49 + 576) = 25.
The volume of a cone of radius 7 cm and height 24 cm (π = 22/7) is
- 616 cm³
- 3696 cm³
- 1232 cm³
- 550 cm³
Answer
C. 1232 cm³
⅓ × 22/7 × 49 × 24 = 1232.
The curved surface area of a cone of radius 7 cm and slant height 25 cm (π = 22/7) is
- 1100 cm²
- 1232 cm²
- 550 cm²
- 154 cm²
Answer
C. 550 cm²
π r l = 22/7 × 7 × 25 = 550.
The surface area of a sphere of radius 7 cm (π = 22/7) is
- 1437 cm²
- 462 cm²
- 154 cm²
- 616 cm²
Answer
D. 616 cm²
4 × 22/7 × 49 = 616.
The volume of a sphere of radius 21 cm (π = 22/7) is
- 12936 cm³
- 38808 cm³
- 5544 cm³
- 1848 cm³
Answer
B. 38808 cm³
4/3 × 22/7 × 9261 = 38808.
The total surface area of a solid hemisphere of radius 7 cm (π = 22/7) is
- 462 cm²
- 616 cm²
- 308 cm²
- 154 cm²
Answer
A. 462 cm²
3πr² = 3 × 154 = 462.
A metal sphere of radius 6 cm is melted and recast into small spheres of radius 2 cm. The number of small spheres is
- 9
- 3
- 27
- 36
Answer
C. 27
The number is (6/2)³ = 27 because the volume is conserved.
A cone and a cylinder have the same base and height. The ratio of the volume of the cone to that of the cylinder is
- 1 : 2
- 1 : 3
- 2 : 3
- 3 : 1
Answer
B. 1 : 3
The cone's volume is one-third of the cylinder's.
If the edge of a cube is doubled, its volume becomes
- 8 times
- 2 times
- 6 times
- 4 times
Answer
A. 8 times
Volume scales as k³ = 8.
The radius of a circle is increased by 10%. The area increases by
- 10%
- 20%
- 11%
- 21%
Answer
D. 21%
(1.1)² = 1.21.
A rectangular tank is 5 m × 4 m × 3 m. How many litres of water can it hold when full?
- 60
- 600
- 6,000
- 60,000
Answer
D. 60,000
Volume 60 m³ and 1 m³ = 1000 litres.
A wire 44 cm long is bent into a circle (π = 22/7). The area enclosed is
- 49 cm²
- 154 cm²
- 616 cm²
- 308 cm²
Answer
B. 154 cm²
2πr = 44 gives r = 7 and area 154.
A square has a diagonal of 12 cm. Its area is
- 36 cm²
- 48 cm²
- 72 cm²
- 144 cm²
Answer
C. 72 cm²
Area = d²/2 = 72.
A 20 m × 15 m park has a 2 m wide path all round it outside. The area of the path is
- 156 m²
- 136 m²
- 140 m²
- 176 m²
Answer
A. 156 m²
Outer 24 × 19 = 456, minus 300 = 156.
A right triangular prism has a triangular base with base 6 cm and height 4 cm, and length 10 cm. Its volume is
- 60 cm³
- 24 cm³
- 120 cm³
- 240 cm³
Answer
C. 120 cm³
Volume = ½ × 6 × 4 × 10 = 120.
A rectangle has perimeter 30 cm and length 9 cm. Its area is
- 54 cm²
- 81 cm²
- 135 cm²
- 27 cm²
Answer
A. 54 cm²
Breadth = 15 − 9 = 6, so the area is 54.
The perimeter of a semicircle of radius 7 cm (π = 22/7) is
- 44 cm
- 36 cm
- 29 cm
- 22 cm
Answer
B. 36 cm
πr + 2r = 22 + 14 = 36.
Cylinders of equal height have radii in the ratio 2 : 3. Their volumes are in the ratio
- 2 : 3
- 3 : 2
- 8 : 27
- 4 : 9
Answer
D. 4 : 9
Volume ∝ r², so the ratio is 4 : 9.
The volume of the frustum of a cone with radii R and r and height h is
- (πh/3)(R + r)²
- πh(R + r)
- (πh/3)(R² + Rr + r²)
- (πh/3)(R² − r²)
Answer
C. (πh/3)(R² + Rr + r²)
This is the standard frustum formula.
1 cubic metre is equal to
- 1000 litres
- 10,000 litres
- 10 litres
- 100 litres
Answer
A. 1000 litres
1 m³ = 10⁶ cm³ = 1000 litres.
Which of the statements is/are correct? 1. The volume of a cone is one-third of that of a cylinder with the same base and height. 2. The curved surface area of a cylinder is πr²h.
- 1 only
- 2 only
- Both 1 and 2
- Neither 1 nor 2
Answer
A. 1 only
The curved surface area is 2πrh.
Which of the statements is/are correct? 1. The volume of a sphere is (4/3)πr³. 2. The surface area of a sphere is 4πr².
- 1 only
- 2 only
- Both 1 and 2
- Neither 1 nor 2
Answer
C. Both 1 and 2
Both are the standard sphere formulas.
Which of the statements is/are correct? 1. The area of a circle is 2πr. 2. The area of a trapezium is ½ × (sum of parallel sides) × height.
- 1 only
- 2 only
- Both 1 and 2
- Neither 1 nor 2
Answer
B. 2 only
2πr is the circumference; the area is πr².
Which of the statements is/are correct? 1. The total surface area of a cube is 4a². 2. The volume of a cube is 6a³.
- 1 only
- 2 only
- Both 1 and 2
- Neither 1 nor 2
Answer
D. Neither 1 nor 2
TSA = 6a² and volume = a³.
Which of the statements is/are correct? 1. The slant height of a cone is l = √(r² + h²). 2. The curved surface area of a cone is πrh.
- 1 only
- 2 only
- Both 1 and 2
- Neither 1 nor 2
Answer
A. 1 only
The curved surface area is πrl with the slant height l.
Which of the statements is/are correct? 1. If every linear dimension of a solid is doubled, the surface area becomes 4 times. 2. In the same case, the volume becomes 8 times.
- 1 only
- 2 only
- Both 1 and 2
- Neither 1 nor 2
Answer
C. Both 1 and 2
Area scales as k² and volume as k³.
Which of the statements is/are correct? 1. The curved surface area of a hemisphere is 2πr². 2. The total surface area of a hemisphere is 2πr².
- 1 only
- 2 only
- Both 1 and 2
- Neither 1 nor 2
Answer
A. 1 only
The total surface area includes the flat top and is 3πr².
Match the solid with its volume: (a) cylinder, (b) cone, (c) sphere. The correct formulas in order are
- πr²h, (4/3)πr³, ⅓πr²h
- πr²h, ⅓πr²h, (4/3)πr³
- ⅓πr²h, πr²h, 4πr²
- 2πrh, πrl, 4πr²
Answer
B. πr²h, ⅓πr²h, (4/3)πr³
These are the standard volume formulas.
A parallelogram has base 12 cm and height 7 cm. Its area is
- 19 cm²
- 42 cm²
- 168 cm²
- 84 cm²
Answer
D. 84 cm²
Area = base × height = 84.