AP Police Constable practice question
A bacterial culture's population multiplies to become 21 times its initial size overnight. A student needs log₁₀(21) to estimate growth stages. Given log 3 = 0.4771 and log 7 = 0.8451, find log₁₀(21).
From a AP Police Constable Quantitative Aptitude practice set · Quantitative Aptitude
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Correct answer: (C) 1.3222
21 = 3 × 7, so log 21 = log 3 + log 7 = 0.4771 + 0.8451 = 1.3222.
हिंदी में प्रश्न
एक जीवाणु संवर्धन (culture) की जनसंख्या रात भर में अपने प्रारंभिक आकार से 21 गुना हो जाती है। वृद्धि चरणों का अनुमान लगाने हेतु एक छात्र को log₁₀(21) चाहिए। log 3 = 0.4771 और log 7 = 0.8451 देते हुए log₁₀(21) ज्ञात करें।
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सही उत्तर: (C) 1.3222
21 = 3 × 7, अतः log 21 = log 3 + log 7 = 0.4771 + 0.8451 = 1.3222.
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