RRB NTPC CBT-1 practice question
A body is dropped from rest from a height of 45 m. The time it takes to reach the ground (g = 10 m s⁻²) is:
From a RRB NTPC CBT-1 General Awareness practice set · General Awareness
Tap an option to check your answer.
Show answer and explanation
Correct answer: (C) 3 s
h = ½gt² → 45 = ½ × 10 × t², so t² = 9 and t = 3 s. **తె:** 3 సెకన్లు.
हिंदी में प्रश्न
45 మీ. ఎత్తు నుంచి నిశ్చల స్థితిలో ఒక వస్తువును వదిలితే నేలను చేరడానికి పట్టే సమయం (g = 10 మీ/సె²)?
उत्तर जाँचने के लिए किसी विकल्प पर टैप करें।
उत्तर और व्याख्या देखें
सही उत्तर: (C) 3 సె
h = ½gt² → 45 = ½ × 10 × t², अतः t² = 9 और t = 3 सेकंड। **हिंदी:** 3 सेकंड।
More solved General Awareness questions
- The slogan 'Simon Go Back', raised during the nationwide protests of 1928 against the Simon Commission, is credited to:
- The UP Cabinet approved the Uttar Pradesh Data Centre Policy 2026 to establish the state as a hub for which type of data centres?
- What should come in place of ? in the given series? 91 97 106 118 133 ?
- A school teacher noticed that 6 years ago, his age was 4 times the age of his daughter at that time. 6 years from now, the teacher's age…
- A sound wave has a frequency of 4 kHz and a wavelength of 25 cm. How much time will it take to travel a distance of 2.5 km?
- Find the compound interest on ₹12000 at 12% per annum for 2 years, compounded annually.