RRB NTPC CBT-1 previous year question
A cylindrical tank has a diameter of 12 m and a height of 10 m. If the tank is closed at both ends, what is the ratio of its curved surface area to its total surface area?
Asked in RRB NTPC 2026 — 14 June Shift 2 · Quantitative Aptitude
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Correct answer: (B) 5:8
CSA = 2*pi*r*h = 2*pi*6*10 = 120*pi; TSA = 2*pi*r*(r+h) = 2*pi*6*16 = 192*pi. The ratio CSA:TSA = 120:192 = 5:8.
हिंदी में प्रश्न
एक बेलनाकार टैंक का व्यास 12 और ऊँचाई 10 mel यदि टेंक के दोनों सिरे बंद हैं, तो इसके पृष्ठीय क्षेत्रफल और संपूर्ण पृष्ठीय क्षेत्रफल का अनुपात क्या होगा?
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उत्तर और व्याख्या देखें
सही उत्तर: (B) 2:5
CSA = 2*pi*r*h = 2*pi*6*10 = 120*pi है; TSA = 2*pi*r*(r+h) = 2*pi*6*16 = 192*pi है। CSA:TSA का अनुपात = 120:192 = 5:8 है।
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