SSC CHSL Tier-1 previous year question
A fraction's denominator is 5 more than its numerator. Adding 3 to both gives 2/3. Find the original fraction.
Asked in SSC CHSL Tier-1 (14 Nov 2025 Shift 1) · Quantitative Aptitude
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Correct answer: (C) 7/12
Let fraction = n/(n+5). (n+3)/(n+8)=2/3 → 3n+9=2n+16 → n=7. Fraction = 7/12.
हिंदी में प्रश्न
एक भिन्न का हर उसके अंश से 5 अधिक है। दोनों में 3 जोड़ने पर नई भिन्न 2/3 हो जाती है। मूल भिन्न ज्ञात कीजिए।
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उत्तर और व्याख्या देखें
सही उत्तर: (C) 7/12
मान लीजिए भिन्न = n/(n+5)। (n+3)/(n+8)=2/3 → n=7। भिन्न = 7/12.
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