SSC GD Constable previous year question
A hemispherical bowl has a radius of 3.5 cm. It is to be painted on both the inside and outside. Find the cost of painting it at the rate of ₹15 per 10 cm² (use π = 22/7).
Asked in SSC GD Constable 2025: 06 Feb 2025 Shift 1 (Morning) · Quantitative Aptitude
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Correct answer: (C) ₹231
Curved surface area of hemisphere = 2πr² = 2×(22/7)×3.5×3.5 = 77 cm². Painting both sides = 2×77 = 154 cm². Cost = (154/10)×15 = ₹231.
हिंदी में प्रश्न
एक अर्धगोलाकार कटोरे की त्रिज्या 3.5 cm है। इसे अंदर और बाहर दोनों तरफ से पेंट किया जाना है। ₹15 प्रति 10 cm² की दर से इसे पेंट करने की लागत ज्ञात कीजिए। (π = 22/7 का उपयोग करें।)
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सही उत्तर: (C) ₹231
अर्धगोले का वक्र पृष्ठीय क्षेत्रफल = 2πr² = 2×(22/7)×3.5×3.5 = 77 cm²। दोनों तरफ पेंट = 2×77 = 154 cm²। लागत = (154/10)×15 = ₹231।
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