SSC CHSL Tier-1 practice question
A hollow cylindrical pipe has an external radius of 42 cm and an internal radius of 28 cm. If its height is 5 cm, find the volume of material used to make the pipe. (Use π = 22/7)
From a SSC CHSL Tier-1 Quantitative Aptitude practice set · Quantitative Aptitude
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Correct answer: (D) 15400 cm³
Volume of material = π(R²-r²)h = (22/7) × (42² - 28²) × 5 = (22/7) × 980 × 5 = 15400 cm³.
हिंदी में प्रश्न
एक खोखले बेलनाकार पाइप की बाह्य त्रिज्या 42 सेमी और आंतरिक त्रिज्या 28 सेमी है। यदि इसकी ऊँचाई 5 सेमी है, तो पाइप बनाने में प्रयुक्त सामग्री का आयतन ज्ञात करें। (π = 22/7 का प्रयोग करें)
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सही उत्तर: (D) 15400 सेमी³
सामग्री का आयतन = π(R²-r²)h = (22/7) × (42² - 28²) × 5 = (22/7) × 980 × 5 = 15400 सेमी³।
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