SSC CHSL Tier-1 previous year question
A man walks up a moving-up escalator in 30s and down the same escalator in 90s. How long to walk up when it's stationary?
Asked in SSC CHSL Tier-1 (14 Nov 2025 Shift 2) · Quantitative Aptitude
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Correct answer: (A) 45 seconds
Let w=walking speed, e=escalator speed. Up: N=(w+e)30. Down: N=(w−e)90. Solving gives w=2e, N=90e. Stationary time = N/w = 90e/2e = 45 seconds.
हिंदी में प्रश्न
एक व्यक्ति ऊपर की ओर चलने वाले एस्के लेटर पर 30 सेकं ड में चढ़ सकता है और उसी एस्के लेटर पर नीचे 90 सेकं ड में उतर सकता है। एस्के लेटर स्थिर होने पर चढ़ने में कितना समय लगेगा?
उत्तर जाँचने के लिए किसी विकल्प पर टैप करें।
उत्तर और व्याख्या देखें
सही उत्तर: (A) 45 सेकं ड
हल करने पर w=2e, N=90e। स्थिर एस्के लेटर पर समय = N/w = 45 सेकं ड।
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