AP Police Constable practice question
A trader mixes three grades of tea: Grade X, 6 kg at Rs 100/kg; Grade Y, an unknown quantity at Rs 150/kg; and Grade Z, 4 kg at Rs 200/kg. If the average cost price of the entire mixture is Rs 145/kg, find the quantity of Grade Y used.
From a AP Police Constable Quantitative Aptitude practice set · Quantitative Aptitude
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Correct answer: (A) 10 kg
Let quantity of Y be y kg. Total cost = 6×100 + y×150 + 4×200 = 600 + 150y + 800 = 1400 + 150y. Total weight = 10 + y. Given average = 145: (1400 + 150y)/(10 + y) = 145. So 1400 + 150y = 1450 + 145y, giving 5y = 50, y = 10 kg.
हिंदी में प्रश्न
एक व्यापारी तीन प्रकार की चाय मिलाता है: ग्रेड X, 6 kg, Rs 100/kg पर; ग्रेड Y, अज्ञात मात्रा, Rs 150/kg पर; और ग्रेड Z, 4 kg, Rs 200/kg पर। यदि पूरे मिश्रण का औसत लागत मूल्य Rs 145/kg है, तो ग्रेड Y की मात्रा ज्ञात करें।
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सही उत्तर: (A) 10 kg
मान लीजिए Y की मात्रा y kg है। कुल लागत = 6×100 + y×150 + 4×200 = 600 + 150y + 800 = 1400 + 150y। कुल भार = 10 + y। दिया गया औसत = 145: (1400 + 150y)/(10 + y) = 145। अतः 1400 + 150y = 1450 + 145y, जिससे 5y = 50, y = 10 kg।
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