SSC CPO practice question
Arjun walks 9 km east, then 12 km south, then 6 km north. How far is Arjun from the starting point?
From a SSC CPO Reasoning practice set · Reasoning
Tap an option to check your answer.
Show answer and explanation
Correct answer: (D) 10.82 km
Net southward displacement = 12-6 = 6 km; distance = sqrt(92+62) = 10.82 km.
शुद्ध दक्षिण दिशा में विस्थापन = 12-6 = 6 किमी; दूरी = sqrt(92+62) = 10.82 किमी।
शुद्ध दक्षिण दिशा में विस्थापन = 12-6 = 6 किमी; दूरी = sqrt(92+62) = 10.82 किमी।
हिंदी में प्रश्न
अर्जुन 9 किमी पूर्व, फिर 12 किमी दक्षिण, फिर 6 किमी उत्तर चलता/चलती है। अर्जुन प्रारंभिक बिंदु से कितनी दूर है?
उत्तर जाँचने के लिए किसी विकल्प पर टैप करें।
उत्तर और व्याख्या देखें
सही उत्तर: (D) 10.82 किमी
Net southward displacement = 12-6 = 6 km; distance = sqrt(92+62) = 10.82 km.
शुद्ध दक्षिण दिशा में विस्थापन = 12-6 = 6 किमी; दूरी = sqrt(92+62) = 10.82 किमी।
शुद्ध दक्षिण दिशा में विस्थापन = 12-6 = 6 किमी; दूरी = sqrt(92+62) = 10.82 किमी।
More solved Reasoning questions
- A shopkeeper bought an item for ₹817 and sold it at a profit of 10%. What is the selling price?
- Sanjay walks 18 km west, then 24 km south. How far is Sanjay from the starting point?
- Find the missing number in the series: 4, 12, 36, 108, ?
- Select the option that is related to the third number in the same way as the second number is related to the first number. 3 : 27 :: 13 : ?
- In a row of 40 students, Arjun is 15th from the left. Find his position from the right.
- What should come in place of '?' in the given series? 4, 9, 25, 49, ?