RRB Technician Grade 3 practice question
Consider several electric bulbs designed to be used on a 240 V electric supply line. The bulbs are rated as 10 W. How many bulbs can be connected in parallel with each other across the two wires of the 240 V line if the maximum allowable current is 8 A?
From a RRB Technician Grade 3 Science practice set · Science
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Correct answer: (D) 192
Each 10 W bulb on a 240 V line draws current = P/V = 10/240 A. The number of bulbs in parallel for a total current of 8 A = 8/(10/240) = 8x240/10 = 192.
हिंदी में प्रश्न
दो बल्बों में से एक बल्ब दूसरे बल्ब की तुलना में अधिक प्रकाशमान होता है। किस बल्ब का प्रतिरोध उच्च है? (एक ही वोल्टता स्रोत के साथ एक-एक करके दो बल्बों को जोड़ना, एक साथ नहीं)
उत्तर जाँचने के लिए किसी विकल्प पर टैप करें।
उत्तर और व्याख्या देखें
सही उत्तर: (D) मंद बल्ब
240 V लाइन पर प्रत्येक 10 W बल्ब में धारा = P/V = 10/240 A प्रवाहित होती है। कुल 8 A धारा के लिए समांतर क्रम में बल्बों की संख्या = 8/(10/240) = 8x240/10 = 192 होगी।
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