RRB Technician Grade 3 previous year question
Find the product of the common prime factors of the numbers 1950, 1560 and 2340.
Asked in RRB Technician Grade 3 (06 Mar 2026 Shift 1) · Quantitative Aptitude
Tap an option to check your answer.
Show answer and explanation
Correct answer: (B) 390
Factorising: 1950=2x3x52x13, 1560=23x3x5x13, 2340=22x32x5x13. The common prime factors are 2, 3, 5 and 13, whose product is 2x3x5x13=390.
हिंदी में प्रश्न
संख्याओं 1950, 1560 और 2340 के उभयनिष्ठ अभाज्य गुणनखंडों का गुणनफल ज्ञात कीजिए।
उत्तर जाँचने के लिए किसी विकल्प पर टैप करें।
उत्तर और व्याख्या देखें
सही उत्तर: (B) 390
गुणनखंडन से: 1950=2×3×5²×13, 1560=2³×3×5×13, 2340=2²×3²×5×13। उभयनिष्ठ अभाज्य गुणनखंड 2, 3, 5, 13 हैं, जिनका गुणनफल 2×3×5×13=390 है।
More solved Quantitative Aptitude questions
- For a given data, the mean is 48.5 and the median is 44. The mode of the data is:
- The length of one of the two parallel sides of a trapezium is 8 cm, while the length of the other side of this pair of parallel sides is…
- If the surface area of a sphere is 314 cm², find its radius. (Take π = 3.14)
- A, B, C, and D can do a piece of work in 12, 15, 20, and 30 days, respectively. All start together, but D leaves after 2 days, C leaves 3…
- During a sale 50% of the goods are sold at 40% profit, 40% of the remaining goods are sold at 13% profit and the still remaining goods are…
- Two trains of lengths 120 m and 180 m running in opposite directions at speeds of 60 km/h and 75 km/h, respectively. In how many seconds…