RRB NTPC CBT-1 previous year question
Find the smallest number which when divided by 9, 12 and 15 leaves a remainder 3 in each case.
Asked in RRB NTPC 2026 — 15 June Shift 2 · Quantitative Aptitude
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Correct answer: (D) 183
The number leaves remainder 3 when divided by 9, 12, and 15, so it is of the form LCM(9,12,15)+3. LCM(9,12,15)=180, so the smallest such number is 180+3=183.
हिंदी में प्रश्न
वह छोटी से छोटी संख्या ज्ञात कीजिए जिसे 9, 12 और 15 से विभाजित करने पर प्रत्येक स्थिति में शेषफल 3 बचता हो।
उत्तर जाँचने के लिए किसी विकल्प पर टैप करें।
उत्तर और व्याख्या देखें
सही उत्तर: (D) 123
जब संख्या को 9, 12 और 15 से विभाजित किया जाता है तो शेषफल 3 बचता है, इसलिए संख्या LCM(9,12,15)+3 के रूप में होगी। LCM(9,12,15)=180, अतः सबसे छोटी संख्या 180+3=183 है।
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