SSC CHSL Tier-1 previous year question
Find the value of k so that x² + kx + 16 = 0 has real, distinct roots.
Asked in SSC CHSL Tier-1 (12 Nov 2025 Shift 2) · Quantitative Aptitude
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Correct answer: (A) k > 8
For real distinct roots, discriminant k² − 64 > 0 → k² > 64 → k > 8 or k < −8; among options, k > 8 fits.
हिंदी में प्रश्न
k का वह मान ज्ञात कीजिए जिससे x² + kx + 16 = 0 के वास्तविक व भिन्न मूल हों।
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सही उत्तर: (A) k > 8
वास्तविक भिन्न मूलों के लिए विविक्तकर k² − 64 > 0 → k² > 64 → k > 8 या k < −8; विकल्पों में k > 8 सही है।
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