AP Police SI previous year question
If √[(3⁴+3⁷)/7] = x, √[(3²+3⁵)/7] = y and z = √(x+y), then 4(z²+3) =
Asked in AP Police SI Prelims: 2023 (Paper I & II) · Quantitative Aptitude
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Correct answer: (D) 108
(3⁴+3⁷)/7 = 3⁴(1+3³)/7 = 81·28/7 = 324 → x = 18. (3²+3⁵)/7 = 3²(1+3³)/7 = 9·4 = 36 → y = 6. x+y = 24, so z² = 24. 4(24+3) = 108.
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हिंदी में प्रश्न
यदि √[(3⁴+3⁷)/7] = x, √[(3²+3⁵)/7] = y और z = √(x+y) है, तो 4(z²+3) =
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सही उत्तर: (D) 108
(3⁴+3⁷)/7 = 3⁴(1+3³)/7 = 81·28/7 = 324 → x = 18। (3²+3⁵)/7 = 3²(1+3³)/7 = 9·4 = 36 → y = 6। x+y = 24, अतः z² = 24। 4(24+3) = 108।
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