RRB Technician Grade 3 previous year question
If 9A7B is divisible by 55, find A + B.
Asked in RRB Technician Grade 3 (10 Mar 2026 Shift 2) · Quantitative Aptitude
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Correct answer: (D) 5
For 9A7B to be divisible by 55 (5×11), it must be divisible by both 5 and 11. Divisibility by 5 requires B=0 or 5; divisibility by 11 requires (B+A)−(7+9) to be a multiple of 11. Testing both cases gives A+B=5 as the only valid solution.
हिंदी में प्रश्न
यदि 9A7B, 55 से विभाज्य है, तो A + B का मान ज्ञात कीजिए।
उत्तर जाँचने के लिए किसी विकल्प पर टैप करें।
उत्तर और व्याख्या देखें
सही उत्तर: (D) 5
9A7B को 55 (5×11) से विभाज्य होने के लिए 5 और 11 दोनों से विभाज्य होना चाहिए। 5 से विभाज्यता हेतु B=0 या 5 चाहिए; 11 से विभाज्यता हेतु (B+A)−(7+9) 11 का गुणज होना चाहिए। दोनों स्थितियों की जांच करने पर केवल A+B=5 वैध हल है।
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