IBPS PO Prelims practice question
In parallelogram ABCD, angle A = (2x + 30)° and angle C = (3x + 10)°. Find angle A.
From a IBPS PO Prelims Quantitative Aptitude practice set · Quantitative Aptitude
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Correct answer: (B) 70°
Opposite angles of a parallelogram are equal, so angle A = angle C: 2x + 30 = 3x + 10. Solving, x = 20. So angle A = 2(20) + 30 = 70°.
हिंदी में प्रश्न
समांतर चतुर्भुज ABCD में, कोण A = (2x + 30)° और कोण C = (3x + 10)° है। कोण A ज्ञात कीजिए।
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सही उत्तर: (B) 70°
समांतर चतुर्भुज में सम्मुख कोण बराबर होते हैं, इसलिए कोण A = कोण C: 2x + 30 = 3x + 10. हल करने पर x = 20. अतः कोण A = 2(20) + 30 = 70° है।
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