RRB ALP practice question
In triangle ABC, AD is the altitude from A to BC, with D lying between B and C. Angle B = 47° and angle BAC = 101°. Find angle DAC.
From a RRB ALP Quantitative Aptitude practice set · Quantitative Aptitude
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Correct answer: (C) 58°
First, angle C = 180° − 47° − 101° = 32°. In right triangle ADC (right angle at D), angle DAC = 180° − 90° − angle C = 90° − 32° = 58°.
हिंदी में प्रश्न
त्रिभुज ABC में, AD, A से BC पर डाला गया शीर्षलंब है, जहाँ D, B और C के बीच स्थित है। कोण B = 47° तथा कोण BAC = 101° है। कोण DAC ज्ञात कीजिए।
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सही उत्तर: (C) 58°
पहले, कोण C = 180° − 47° − 101° = 32°। समकोण त्रिभुज ADC में (D पर समकोण), कोण DAC = 180° − 90° − कोण C = 90° − 32° = 58°।
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