RRB NTPC CBT-1 practice question
In triangle ABC, D and E are points on sides AB and AC respectively such that DE is parallel to BC. If AD = 7, DB = 14 and AE = 5, find the length of EC.
From a RRB NTPC CBT-1 Quantitative Aptitude practice set · Quantitative Aptitude
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Correct answer: (B) 10 units
By the Basic Proportionality Theorem (Thales' theorem), since DE || BC, AD/DB = AE/EC. So EC = (AE × DB)/AD = (5 × 14)/7 = 10 units.
हिंदी में प्रश्न
त्रिभुज ABC में, D और E क्रमशः भुजाओं AB और AC पर स्थित बिंदु इस प्रकार हैं कि DE, BC के समांतर है। यदि AD = 7, DB = 14 और AE = 5 है, तो EC की लंबाई ज्ञात कीजिए।
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सही उत्तर: (B) 10 इकाई
आधारभूत समानुपातिकता प्रमेय (थेल्स प्रमेय) के अनुसार, चूँकि DE || BC है, इसलिए AD/DB = AE/EC। अतः EC = (AE × DB)/AD = (5 × 14)/7 = 10 इकाई।
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