RPF Constable practice question
Ray OL is perpendicular to ray ON. Rays OE and OF lie between OL and ON, in the order OL, OE, OF, ON, such that angle LOE = 35° and angle EOF = 40°. Find angle FON.
From a RPF Constable Quantitative Aptitude practice set · Quantitative Aptitude
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Correct answer: (B) 15°
Angle LON = 90°, and it is split by OE, OF into angle LOE + angle EOF + angle FON = 90°. So angle FON = 90° − 35° − 40° = 15°.
हिंदी में प्रश्न
किरण OL, किरण ON पर लंब है। किरणें OE और OF, OL और ON के बीच इस क्रम में स्थित हैं — OL, OE, OF, ON — तथा कोण LOE = 35° और कोण EOF = 40° है। कोण FON ज्ञात कीजिए।
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सही उत्तर: (B) 15°
कोण LON = 90° है, जो OE, OF द्वारा कोण LOE + कोण EOF + कोण FON = 90° में विभाजित है। अतः कोण FON = 90° − 35° − 40° = 15° होगा।
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