SSC CPO practice question
Sumeet built a conical tent having a floor diameter of 28 m and a perpendicular height of 48 m. What was the length of a 10 m wide canvas that Sumeet needed for the purpose? [Use π = 22/7]
From a SSC CPO General Awareness practice set · General Awareness
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Correct answer: (B) 220 m
Radius = 14 m, height = 48 m, so slant height l = sqrt(142+482) = sqrt(2500) = 50 m. Curved surface area = pi*r*l = (22/7)x14x50 = 2200 m2. Length of 10 m wide canvas = 2200/10 = 220 m.
हिंदी में प्रश्न
सुमीत ने 28 m व्यास और 48 m ऊँचाई वाला एक शंकु के आकार का त ू बनाया। इस त ू के िलए सुमीत को 10 m चौड़े कैनवास की िकतनी लंबाई की आवश्यकता थी ? [π = 22/7 का प्रयोग कर• ]
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सही उत्तर: (B) 220 m
त्रिज्या = 14 मी, ऊँचाई = 48 मी, अतः तिर्यक ऊँचाई l = sqrt(14²+48²) = sqrt(2500) = 50 मी। वक्र पृष्ठीय क्षेत्रफल = pi*r*l = (22/7)x14x50 = 2200 मी²। 10 मी चौड़े कैनवास की लंबाई = 2200/10 = 220 मी।
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