RRB JE practice question
The average of 5 numbers is 75. If 4 of the numbers are 53, 29, 19, 18, find the remaining number.
From a RRB JE Quantitative Aptitude practice set · Quantitative Aptitude
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Correct answer: (D) 256
Total sum needed = 75 x 5 = 375. Missing number = 375 - 119 = 256.
हिंदी में प्रश्न
5 संख्याओं का औसत 75 है। यदि इनमें से 4 संख्याएँ 53, 29, 19, 18 हैं, तो शेष संख्या ज्ञात कीजिए।
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सही उत्तर: (D) २५६
Total sum needed = 75 x 5 = 375. Missing number = 375 - 119 = 256.
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