RRB Technician Grade 3 practice question
The circumference of a planet is 36,000 km. If the planet makes no other movement and takes 20 hours for one complete rotation, what is the speed of a point on its equator?
From a RRB Technician Grade 3 Science practice set · Science
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Correct answer: (B) 500 m/s
Circumference = 36,000 km = 3.6x107 m, time = 20 h = 72,000 s. Speed = distance/time = 3.6x107/72,000 = 500 m/s.
हिंदी में प्रश्न
एक ग्रह की परिधि 36,000 km है। यदि ग्रह कोई अन्य गति नहीं करता है और एक पूर्ण घूर्णन के लिए 20 घंटे का समय लेता है तो उसके भूमध्य रेखा पर स्थित एक बिंदु की गति क्या होगी?
उत्तर जाँचने के लिए किसी विकल्प पर टैप करें।
उत्तर और व्याख्या देखें
सही उत्तर: (B) 500 मी/से
परिधि = 36,000 किमी = 3.6x107 मीटर, समय = 20 घंटे = 72,000 सेकंड। चाल = दूरी/समय = 3.6x107/72,000 = 500 मीटर/सेकंड।
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