Bihar Police Constable practice question
The length of the transverse common tangent between two non-overlapping circles of radii 50 cm and 45 cm is 168 cm. Find the distance between the centres of the two circles.
From a Bihar Police Constable Quantitative Aptitude practice set · Quantitative Aptitude
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Correct answer: (B) 193 cm
Using L² = d² − (r1 + r2)², we get d² = L² + (r1 + r2)². Here r1 + r2 = 95 cm and L = 168 cm, so d² = 168² + 95² = 28224 + 9025 = 37249. Hence d = √37249 = 193 cm.
हिंदी में प्रश्न
50 सेमी और 45 सेमी त्रिज्या वाले दो वृत्तों (जो एक-दूसरे को नहीं काटते) की तिर्यक उभयनिष्ठ स्पर्श रेखा की लंबाई 168 सेमी है। दोनों वृत्तों के केंद्रों के बीच की दूरी ज्ञात कीजिए।
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सही उत्तर: (B) 193 सेमी
L² = d² − (r1 + r2)² से d² = L² + (r1 + r2)² प्राप्त होता है। यहाँ r1 + r2 = 95 सेमी और L = 168 सेमी है, अतः d² = 168² + 95² = 28224 + 9025 = 37249। अतः d = √37249 = 193 सेमी।
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