RRB NTPC CBT-1 previous year question
The sum of the present ages of a father and his son is 50 years. Five years ago, the father’s age was three times the son’s age. By how many years is the father older than his son?
Asked in RRB NTPC 2026 — 15 June Shift 3 · Quantitative Aptitude
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Correct answer: (D) 20
Let father=f, son=s, with f+s=50. Five years ago, f-5=3(s-5), giving f=3s-10. Substituting: 3s-10+s=50, so s=15 and f=35. The father is older by 35-15=20 years.
हिंदी में प्रश्न
एक पिता और उसके पुत्र की वर्तमान आयु का योग 50 वर्ष है। पाँच वर्ष पहले, पिता की आयु उसके पुत्र की आयु को तीन गुनी थी। पिता अपनी पुत्र से कितने वर्ष बड़ा है?
उत्तर जाँचने के लिए किसी विकल्प पर टैप करें।
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सही उत्तर: (D) 21
मान लें पिता=f, पुत्र=s, जहाँ f+s=50। पाँच वर्ष पहले, f-5=3(s-5), जिससे f=3s-10। प्रतिस्थापित करने पर: 3s-10+s=50, अतः s=15 और f=35। पिता पुत्र से 35-15=20 वर्ष बड़े हैं।
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