Delhi Police Constable practice question
Train A is 260 m long and crosses a platform of length 160 m in 28 seconds. Train B is 340 m long and passes a stationary man in 20 seconds. Both trains travel at constant speeds on parallel straight tracks. Find the time (in seconds) taken when the faster train completely overtakes the slower train while moving in the same direction?
From a Delhi Police Constable General Awareness practice set · General Awareness
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Correct answer: (B) 300
Train A's speed = (260+160)/28 = 15 m/s; Train B's speed = 340/20 = 17 m/s; relative speed while overtaking = 2 m/s, so time = (260+340)/2 = 300 seconds.
हिंदी में प्रश्न
ट्रेन A की लंबाई 260 m है जो 160 m लंबे प्लेटफॉर्म को 28 सेकंड में पार करती है। ट्रेन B की लंबाई 340 m है जो एक स्थिर खड़े हुए व्यक्ति को 20 सेकंड में पार करती है। दोनों ट्रेनें समानांतर, सीधी पटरियों पर नियत चाल से चलती हैं। समान दिशा में चलते हुए, तेज चाल वाली ट्रेन द्वारा धीमी चाल वाली ट्रेन को पूरी तरह से पार करने में लगने वाला समय (सेकंड में) ज्ञात कीजिए।
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सही उत्तर: (B) 300
ट्रेन A की गति = (260+160)/28 = 15 मी/से; ट्रेन B की गति = 340/20 = 17 मी/से; ओवरटेक करते समय सापेक्ष गति = 2 मी/से, अतः समय = (260+340)/2 = 300 सेकंड.
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