RRB JE practice question
Two resistances of 30 Ω each are connected in parallel. This combination is then connected in series with a third resistance of 25 Ω and a 6 V battery. The power supplied by the battery will be _______.
From a RRB JE Science practice set · Science
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Correct answer: (D) 0.90 W
Parallel resistance = 30/2 = 15 Ω. Total resistance = 15 + 25 = 40 Ω. Power = V²/R = 6²/40 = 0.90 W.
हिंदी में प्रश्न
30 Ω के दो प्रतिरोध समांतर क्रम में जुड़े हैं। यह संयोजन एक तीसरे 25 Ω प्रतिरोध और 6 V बैटरी के साथ श्रेणीक्रम में जुड़ा है। बैटरी द्वारा प्रदत्त शक्ति _______ होगी।
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उत्तर और व्याख्या देखें
सही उत्तर: (D) 0.90 W
समांतर प्रतिरोध = 30/2 = 15 Ω। कुल प्रतिरोध = 15 + 25 = 40 Ω। शक्ति = V²/R = 6²/40 = 0.90 W।
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