SSC GD Constable previous year question
What is the value of 2/(1×3) + 2/(3×5) + 2/(5×7) + ..... + 2/(99×101)?
Asked in SSC GD Constable 2024: 22 Feb 2024 Shift 4 · Quantitative Aptitude
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Correct answer: (C) 100/101
The series telescopes: 2/((2k−1)(2k+1)) = 1/(2k−1)−1/(2k+1), so the sum from k=1 to 50 is 1−1/101 = 100/101.
हिंदी में प्रश्न
2/(1×3) + 2/(3×5) + 2/(5×7) + ..... + 2/(99×101) का मान कितना है?
उत्तर जाँचने के लिए किसी विकल्प पर टैप करें।
उत्तर और व्याख्या देखें
सही उत्तर: (C) 101/102
The series telescopes: 2/((2k−1)(2k+1)) = 1/(2k−1)−1/(2k+1), so the sum from k=1 to 50 is 1−1/101 = 100/101.
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