RRB JE practice question
A boy walks from one end A to the other end B of a straight 1000 m road in 2 minutes and then turns around and walks 400 m back to point C in another 2 minutes. What will be the average velocity (in m/s) of the boy in going from point A to point C?
From a RRB JE Science practice set · Science
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Correct answer: (B) 2.5
Total time from A to C = 2 min + 2 min = 240 s. Net displacement from A to C = 1000 m minus 400 m = 600 m. Average velocity = 600/240 = 2.5 m/s.
हिंदी में प्रश्न
एक लड़का 1000 m सीधी सड़क के एक छोर A से दूसरे छोर B तक 2 मिनट में चलता है और फिर मुड़कर 2 मिनट में 400 m चलकर बिंदु C पर वापस आता है। बिंदु A से बिंदु C तक जाने में लड़के का औसत वेग ( m/s में) कितना होगा?
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सही उत्तर: (B) 2.5
A से C तक कुल समय = 2 + 2 = 4 मिनट = 240 सेकंड। A से C तक कुल विस्थापन = 1000 - 400 = 600 मीटर। औसत वेग = 600/240 = 2.5 मीटर/सेकंड।
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