RRB JE practice question
An element 'B' has two isotopes B-10 and B-11 with natural abundance 20% and 80% respectively. What is the average atomic mass of B?
From a RRB JE Science practice set · Science
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Correct answer: (C) 10.8 u
Average atomic mass = (mass1×%abundance1 + mass2×%abundance2)/100 = (10×20 + 11×80)/100 = 10.8 u.
हिंदी में प्रश्न
किसी तत्व 'B' के दो समस्थानिक B-10 और B-11 हैं जिनकी प्राकृतिक बहुलता क्रमशः 20% और 80% है। B का औसत परमाणु द्रव्यमान क्या है?
उत्तर जाँचने के लिए किसी विकल्प पर टैप करें।
उत्तर और व्याख्या देखें
सही उत्तर: (C) 10.8 u
औसत परमाणु द्रव्यमान = (द्रव्यमान1×%बहुलता1 + द्रव्यमान2×%बहुलता2)/100 = (10×20 + 11×80)/100 = 10.8 u।
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