RRB Technician Grade 3 previous year question
A cylindrical printing drum of length 2.1 m makes 350 complete revolutions and prints 4158 m² of fabric. What is the radius of the drum? (Take π = 22/7)
Asked in RRB Technician Grade 3 (06 Mar 2026 Shift 2) · Quantitative Aptitude
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Correct answer: (C) 90 cm
Area printed = 2 x pi x r x length x revolutions. So r = 4158/(2 x 22/7 x 2.1 x 350) = 0.9 m = 90 cm.
हिंदी में प्रश्न
2.1 m लंबाई का एक बेलनाकार प्रिंटिंग ड्रम 350 पूर्ण चक्कर लगाता है और 4158 m² कपड़ा प्रिंट करता है। ड्रम की त्रिज्या कितनी होगी? (π = 22/7 लीजिए)
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उत्तर और व्याख्या देखें
सही उत्तर: (C) 90 cm
मुद्रित क्षेत्रफल = 2×π×r×लंबाई×चक्कर। अतः r = 4158/(2×22/7×2.1×350) = 0.9 मी = 90 सेमी।
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