RRB Technician Grade 3 previous year question
Anisha borrowed ₹28,260 from her friend at 9% per annum, simple interest. She returned the amount after 9 months. How much interest did she pay?
Asked in RRB Technician Grade 3 (06 Mar 2026 Shift 2) · Quantitative Aptitude
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Correct answer: (C) ₹1907.55
Simple Interest = P x R x T / 100 = 28260 x 9 x (9/12) / 100 = Rs.1907.55, using 9 months as 9/12 of a year.
हिंदी में प्रश्न
अनीशा ने अपनी सहेली से 9% वार्षिक साधारण ब्याज पर ₹28,260 उधार लिए। उसने 9 माह बाद मिश्रधन लौटा दिया। उसने ब्याज के रूप में कितना भुगतान किया?
उत्तर जाँचने के लिए किसी विकल्प पर टैप करें।
उत्तर और व्याख्या देखें
सही उत्तर: (C) ₹1907.55
साधारण ब्याज = P×R×T/100 = 28260×9×(9/12)/100 = ₹1907.55, जहाँ 9 महीनों को वर्ष के 9/12 भाग के रूप में लिया गया है।
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