RRB JE practice question
A society has 12 eligible members, out of whom a panel of 3 members is to be selected. In how many ways can the panel be formed?
From a RRB JE Quantitative Aptitude practice set · Quantitative Aptitude
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Correct answer: (C) 220
We need to choose 3 objects out of 12 distinct objects where the order of selection does not matter, so we use combinations: nCr = n! / (r!(n-r)!). Here n = 12 and r = 3, so the number of ways = 12C3 = 220.
हिंदी में प्रश्न
एक सोसाइटी में 12 योग्य सदस्य हैं, जिनमें से 3 सदस्यों का एक पैनल चुना जाना है। यह पैनल कितने तरीकों से बनाया जा सकता है?
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सही उत्तर: (C) 220
हमें 12 अलग-अलग वस्तुओं में से 3 वस्तुएँ चुननी हैं, जहाँ चयन का क्रम मायने नहीं रखता, इसलिए हम संयोजन (combination) सूत्र nCr = n! / (r!(n-r)!) का उपयोग करते हैं। यहाँ n = 12 और r = 3 है, इसलिए तरीकों की संख्या = 12C3 = 220 है।
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