SSC CPO practice question
A train 160 m long running at 54 km/hr crosses a man walking in the opposite direction at 7 km/hr. Find the time taken to cross him.
From a SSC CPO Quantitative Aptitude practice set · Quantitative Aptitude
Tap an option to check your answer.
Show answer and explanation
Correct answer: (D) 9.4 sec
Relative speed = (54+7) km/hr = 61x5/18 = 16.94 m/s. Time = 160/16.94 = 9.4 sec.
हिंदी में प्रश्न
160 मीटर लंबी एक ट्रेन 54 किमी/घंटा की चाल से चलते हुए, विपरीत दिशा में 7 किमी/घंटा की चाल से चल रहे एक व्यक्ति को पार करती है। उसे पार करने में लगा समय ज्ञात करें।
उत्तर जाँचने के लिए किसी विकल्प पर टैप करें।
उत्तर और व्याख्या देखें
सही उत्तर: (D) 9.4 sec
Relative speed = (54+7) km/hr = 61x5/18 = 16.94 m/s. Time = 160/16.94 = 9.4 sec.
More solved Quantitative Aptitude questions
- Find the area of a triangle with base 76 units and height 10 units.
- A sold an item to B at 10% profit, B sold it to C at 25% profit, C sold it to D at 20% loss. D paid Rs.396. A's cost price (Rs.) is
- Find the fourth proportional to 19, 15, and 12.
- A person sold an article at a loss of 12%. If he had sold it for ₹80 more, he would have gained 5%. Find the cost price of the article.
- In rectangle ABCD, diagonals AC and BD intersect at O. Angle AOB = (6x + 5)° and angle BOC = (3x + 40)°. Find angle BOC.
- Asha, a dealer, claims to sell at cost price but actually weighs only 710 g when he should weigh 1000 g. What is his gain percent?