SSC CPO practice question
In rectangle ABCD, diagonals AC and BD intersect at O. Angle AOB = (6x + 5)° and angle BOC = (3x + 40)°. Find angle BOC.
From a SSC CPO Quantitative Aptitude practice set · Quantitative Aptitude
Tap an option to check your answer.
Show answer and explanation
Correct answer: (B) 85°
Since A, O, C are collinear (O lies on diagonal AC), angle AOB and angle BOC form a linear pair: (6x + 5) + (3x + 40) = 180. This gives 9x + 45 = 180, so x = 15. Then angle AOB = 95° and angle BOC = 85°. Hence angle BOC = 85°.
हिंदी में प्रश्न
आयत ABCD में, विकर्ण AC और BD बिंदु O पर प्रतिच्छेद करते हैं। कोण AOB = (6x + 5)° और कोण BOC = (3x + 40)° है। कोण BOC ज्ञात कीजिए।
उत्तर जाँचने के लिए किसी विकल्प पर टैप करें।
उत्तर और व्याख्या देखें
सही उत्तर: (B) 85°
चूंकि A, O, C एक सरल रेखा में हैं (O विकर्ण AC पर स्थित है), कोण AOB और कोण BOC एक रैखिक युग्म बनाते हैं: (6x + 5) + (3x + 40) = 180। इससे 9x + 45 = 180, अतः x = 15। तब कोण AOB = 95° और कोण BOC = 85°। अतः कोण BOC = 85°।
More solved Quantitative Aptitude questions
- Find the area of a triangle with base 76 units and height 10 units.
- A sold an item to B at 10% profit, B sold it to C at 25% profit, C sold it to D at 20% loss. D paid Rs.396. A's cost price (Rs.) is
- Find the fourth proportional to 19, 15, and 12.
- A person sold an article at a loss of 12%. If he had sold it for ₹80 more, he would have gained 5%. Find the cost price of the article.
- A train 160 m long running at 54 km/hr crosses a man walking in the opposite direction at 7 km/hr. Find the time taken to cross him.
- Asha, a dealer, claims to sell at cost price but actually weighs only 710 g when he should weigh 1000 g. What is his gain percent?