SSC CGL Tier-1 practice question
Find the area of a triangle with base \(7\text{ cm}\) and height \(8\text{ cm}\).
From a SSC CGL Tier-1 Quantitative Aptitude practice set · Quantitative Aptitude
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Correct answer: (A) 28 cm²
The area of a triangle is given by:
\[
\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}
\]
Given:
- Base \(b = 7\text{ cm}\)
- Height \(h = 8\text{ cm}\)
\[
\text{Area} = \frac{1}{2} \times 7 \times 8 = 7 \times 4 = 28\text{ cm}^2
\]
\[
\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}
\]
Given:
- Base \(b = 7\text{ cm}\)
- Height \(h = 8\text{ cm}\)
\[
\text{Area} = \frac{1}{2} \times 7 \times 8 = 7 \times 4 = 28\text{ cm}^2
\]
हिंदी में प्रश्न
\(7\text{ cm}\) आधार और \(8\text{ cm}\) ऊँचाई वाले त्रिभुज का क्षेत्रफल ज्ञात कीजिए।
उत्तर जाँचने के लिए किसी विकल्प पर टैप करें।
उत्तर और व्याख्या देखें
सही उत्तर: (A) 28 सेमी²
त्रिभुज का क्षेत्रफल निम्नलिखित सूत्र द्वारा दिया जाता है:
\[
\text{क्षेत्रफल} = \frac{1}{2} \times \text{आधार} \times \text{ऊँचाई}
\]
दिया गया है:
- आधार \(b = 7\text{ सेमी}\)
- ऊँचाई \(h = 8\text{ सेमी}\)
\[
\text{क्षेत्रफल} = \frac{1}{2} \times 7 \times 8 = 7 \times 4 = 28\text{ सेमी}^2
\]
\[
\text{क्षेत्रफल} = \frac{1}{2} \times \text{आधार} \times \text{ऊँचाई}
\]
दिया गया है:
- आधार \(b = 7\text{ सेमी}\)
- ऊँचाई \(h = 8\text{ सेमी}\)
\[
\text{क्षेत्रफल} = \frac{1}{2} \times 7 \times 8 = 7 \times 4 = 28\text{ सेमी}^2
\]
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