SSC CGL Tier-1 practice question
Find the perimeter of a rectangle with length \(24\text{ cm}\) and breadth \(12\text{ cm}\).
From a SSC CGL Tier-1 Quantitative Aptitude practice set · Quantitative Aptitude
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Correct answer: (D) 72 cm
The perimeter of a rectangle is given by:
\[
\text{Perimeter} = 2(l + b)
\]
Given length \(l = 24\text{ cm}\) and breadth \(b = 12\text{ cm}\):
\[
\text{Perimeter} = 2(24 + 12) = 2 \times 36 = 72\text{ cm}
\]
हिंदी में प्रश्न
\(24\text{ cm}\) लंबाई और \(12\text{ cm}\) चौड़ाई वाले आयत का परिमाप ज्ञात कीजिए।
उत्तर जाँचने के लिए किसी विकल्प पर टैप करें।
उत्तर और व्याख्या देखें
सही उत्तर: (D) 72 सेमी
आयत का परिमाप निम्न सूत्र द्वारा दिया जाता है:
\[
\text{परिमाप} = 2(\text{लंबाई} + \text{चौड़ाई})
\]
दिया है, लंबाई \(l = 24\text{ सेमी}\) तथा चौड़ाई \(b = 12\text{ सेमी}\):
\[
\text{परिमाप} = 2(24 + 12) = 2 \times 36 = 72\text{ सेमी}
\]
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