SSC CGL Tier-1 practice question
Find the perimeter of a rectangle with length 20 cm and breadth 5 cm.
From a SSC CGL Tier-1 Quantitative Aptitude practice set · Quantitative Aptitude
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Correct answer: (C) 50 cm
Given:
$$\text{Length } (l) = 20 \text{ cm}$$
$$\text{Breadth } (b) = 5 \text{ cm}$$
$$\text{Perimeter of rectangle} = 2(l + b) = 2(20 + 5) = 2 \times 25 = 50 \text{ cm}$$
$$\text{Length } (l) = 20 \text{ cm}$$
$$\text{Breadth } (b) = 5 \text{ cm}$$
$$\text{Perimeter of rectangle} = 2(l + b) = 2(20 + 5) = 2 \times 25 = 50 \text{ cm}$$
हिंदी में प्रश्न
20 सेमी लंबाई और 5 सेमी चौड़ाई वाले आयत का परिमाप ज्ञात करें।
उत्तर जाँचने के लिए किसी विकल्प पर टैप करें।
उत्तर और व्याख्या देखें
सही उत्तर: (C) 50 cm
दिया गया है:
$$\text{लंबाई } (l) = 20 \text{ cm}$$
$$\text{चौड़ाई } (b) = 5 \text{ cm}$$
$$\text{आयत का परिमाप} = 2(l + b) = 2(20 + 5) = 2 \times 25 = 50 \text{ cm}$$
$$\text{लंबाई } (l) = 20 \text{ cm}$$
$$\text{चौड़ाई } (b) = 5 \text{ cm}$$
$$\text{आयत का परिमाप} = 2(l + b) = 2(20 + 5) = 2 \times 25 = 50 \text{ cm}$$
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