RRB Technician Grade 3 practice question
Find the sum of the first 40 terms of the arithmetic progression 6, 13, 20, ….
From a RRB Technician Grade 3 Quantitative Aptitude practice set · Quantitative Aptitude
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Correct answer: (A) 5700
a = 6, d = 7, n = 40. Sₙ = n/2 × [2a + (n − 1)d] = 40/2 × [12 + 39 × 7] = 40/2 × 285 = 5700.
हिंदी में प्रश्न
समांतर श्रेढ़ी 6, 13, 20, … के प्रथम 40 पदों का योग ज्ञात कीजिए।
उत्तर जाँचने के लिए किसी विकल्प पर टैप करें।
उत्तर और व्याख्या देखें
सही उत्तर: (A) 5700
a = 6, d = 7, n = 40। Sₙ = n/2 × [2a + (n − 1)d] = 40/2 × [12 + 39 × 7] = 40/2 × 285 = 5700।
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