RRB Technician Grade 3 practice question
The weights of 5 parcels at a post office — four of the five values are 25, 29, 33, 37, and it is known that this fifth value is the SMALLEST of the five values. The mean of all five values is 28, and the mean deviation about the mean of all five values is 6. Find the fifth (missing) value.
From a RRB Technician Grade 3 Quantitative Aptitude practice set · Quantitative Aptitude
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Correct answer: (D) 16 kg
Sum of absolute deviations of all 5 values from the mean = mean deviation × n = 6 × 5 = 30. Absolute deviations of the four known values: |25-28|=3, |29-28|=1, |33-28|=5, |37-28|=9, summing to 18. So |x - mean| = 30 - 18 = 12. Since the missing value is the smallest, it must be less than the mean, so x = mean - 12 = 16 kg.
हिंदी में प्रश्न
एक डाकघर में 5 पार्सलों का भार में से चार मान 25, 29, 33, 37 हैं, और यह ज्ञात है कि यह पाँचवाँ मान इन पाँचों में सबसे छोटा (न्यूनतम) है। पाँचों मानों का माध्य 28 है, और पाँचों मानों के माध्य के सापेक्ष माध्य विचलन 6 है। पाँचवाँ (लुप्त) मान ज्ञात कीजिए।
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सही उत्तर: (D) 16 किग्रा
सभी 5 मानों के माध्य से निरपेक्ष विचलनों का योग = माध्य विचलन × n = 6 × 5 = 30। चार ज्ञात मानों के निरपेक्ष विचलन: |25-28|=3, |29-28|=1, |33-28|=5, |37-28|=9, इनका योग 18 है। अतः |x - माध्य| = 30 - 18 = 12। चूँकि लुप्त मान सबसे छोटा है, यह माध्य से कम होगा, अतः x = माध्य - 12 = 16 किग्रा।
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