SBI Clerk Prelims practice question
Find the value of √(1 + 3 + 5 + … + 15) × √(36 × 38 + 1).
From a SBI Clerk Prelims Quantitative Aptitude practice set · Quantitative Aptitude
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Correct answer: (B) 296
First root: the odd numbers up to 15 are 8 terms, sum = 8², root = 8. Second root: 36 × 38 + 1 = (37 − 1)(37 + 1) + 1 = 37², root = 37. Product = 8 × 37 = 296.
हिंदी में प्रश्न
√(1 + 3 + 5 + … + 15) × √(36 × 38 + 1) का मान ज्ञात कीजिए।
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सही उत्तर: (B) 296
पहला मूल: 15 तक की विषम संख्याएँ 8 पद हैं, योग = 8², मूल = 8। दूसरा मूल: 36 × 38 + 1 = (37 − 1)(37 + 1) + 1 = 37², मूल = 37। गुणनफल = 8 × 37 = 296।
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