RRB Technician Grade 3 previous year question
G is the centroid of the equilateral triangle ABC. If AB = 36 cm, then length (in cm) of AG is:
Asked in RRB Technician Grade 3 (10 Mar 2026 Shift 3) · Quantitative Aptitude
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Correct answer: (D) 12√3
Median of equilateral triangle = (√3/2)*36 = 18√3. Centroid divides median 2:1 from vertex, so AG = (2/3)*18√3 = 12√3.
हिंदी में प्रश्न
समबाहु त्रिभुज ABC का केंद्रक G है। यदि AB = 36 cm है, तो AG की लंबाई (cm में) ज्ञात कीजिए।
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सही उत्तर: (D) 12√3
समबाहु त्रिभुज की माध्यिका = (√3/2)*36 = 18√3। केंद्रक शीर्ष से 2:1 में बांटता है, अतः AG = (2/3)*18√3 = 12√3 सेमी।
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