RRB Technician Grade 3 previous year question
A cylindrical rod has an outer curved surface area of 7900 cm². If the length of the rod is 3 cm, then the outer radius (in cm) of the rod, correct to two places of decimal, is: (Take π = 22/7)
Asked in RRB Technician Grade 3 (10 Mar 2026 Shift 3) · Quantitative Aptitude
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Correct answer: (C) 418.94
CSA = 2πrl, so r = 7900/(2*(22/7)*3) = 7900*7/132 ≈ 418.94 cm.
हिंदी में प्रश्न
किसी बेलनाकार छड़ का बाह्य वक्र पृष्ठीय क्षेत्रफल 7900 cm² है। यदि छड़ की लंबाई 3 cm है, तो छड़ की बाह्य त्रिज्या (cm में) ज्ञात कीजिए (दशमलव के बाद दो स्थानों तक सही)। (π = 22/7 लीजिए)
उत्तर जाँचने के लिए किसी विकल्प पर टैप करें।
उत्तर और व्याख्या देखें
सही उत्तर: (C) 418.94
CSA = 2πrl सूत्र से r = 7900*7/(2*22*3) ≈ 418.94 सेमी प्राप्त होता है।
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