RRB Technician Grade 3 previous year question
When one-third of a number is increased by 10, the result is 65. Find the sum of the digits of the original number.
Asked in RRB Technician Grade 3 (10 Mar 2026 Shift 3) · Quantitative Aptitude
Tap an option to check your answer.
Show answer and explanation
Correct answer: (D) 12
n/3 + 10 = 65 gives n/3 = 55, so n = 165. Sum of digits of 165 = 1+6+5 = 12.
हिंदी में प्रश्न
संख्या के एक-तिहाई में 10 जोड़ने पर 65 प्राप्त होता है। मूल संख्या के अंकों का योग ज्ञात कीजिए।
उत्तर जाँचने के लिए किसी विकल्प पर टैप करें।
उत्तर और व्याख्या देखें
सही उत्तर: (D) 12
n/3 + 10 = 65 से n/3 = 55 अर्थात n = 165। 165 के अंकों का योग = 1+6+5 = 12 है।
More solved Quantitative Aptitude questions
- What sum of money (in ₹) will yield ₹720 as simple interest in 3 years at 8% per annum?
- What sum of money (in ₹) will yield ₹700 as simple interest in 2 years at 8% per annum?
- In a class, there are 36 boys and 24 girls. By what percentage should the number of girls be increased so that it becomes equal to the…
- In a family, the sum of the ages of a father and son is 50 years. 10 years from now, the difference in their ages will be 20 years. Find…
- Which of the following numbers is divisible by both 17 and 13?
- A cylindrical rod has an outer curved surface area of 7900 cm². If the length of the rod is 3 cm, then the outer radius (in cm) of the…