RRB Technician Grade 3 previous year question
If (sinθ + cosθ)/(sinθ − cosθ) = 11, then the value of (25 tan²θ − 3)/(36 cot²θ + 2) − 1 is:
Asked in RRB Technician Grade 3 (09 Mar 2026 Shift 3) · Quantitative Aptitude
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Correct answer: (B) 2/9
From (sinθ+cosθ)/(sinθ−cosθ)=11, solving gives tanθ=6/5, so tan²θ=36/25 and cot²θ=25/36. Substituting: (36−3)/(25+2)−1 = 33/27−1 = 2/9.
हिंदी में प्रश्न
यदि (sinθ + cosθ)/(sinθ − cosθ) = 11 है, तो (25 tan²θ − 3)/(36 cot²θ + 2) − 1 का मान ज्ञात कीजिए।
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सही उत्तर: (B) 2/9
(sinθ+cosθ)/(sinθ−cosθ)=11 से हल करने पर tanθ=6/5, अतः tan²θ=36/25 और cot²θ=25/36। प्रतिस्थापित करने पर: (36−3)/(25+2)−1 = 33/27−1 = 2/9।
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