IBPS RRB Office Assistant (Multipurpose) Prelims practice question
In a race of 900 m, Sita beats Radha by 36 m and beats Geeta by 144 m. If Radha and Geeta were to run a race of 560 m at these same speeds, what start should Radha give Geeta so that the race ends in a dead heat?
From a IBPS RRB Office Assistant (Multipurpose) Prelims Quantitative Aptitude practice set · Quantitative Aptitude
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Correct answer: (D) 70 m
Speed(Sita):Speed(Radha) = 900:864 = 25:24. Speed(Sita):Speed(Geeta) = 900:756 = 25:21. Dividing, Speed(Radha):Speed(Geeta) = [24/25] : [21/25] = 8:7. In a race of 560 m, for a dead heat, Radha should give Geeta a start of 560×(8−7)/8 = 70 m.
हिंदी में प्रश्न
900 मीटर की एक दौड़ में, Sita, Radha को 36 मीटर से तथा Geeta को 144 मीटर से हराता है। यदि Radha और Geeta इन्हीं चालों से 560 मीटर की दौड़ लगाएँ, तो Radha को Geeta को कितनी शुरुआत देनी चाहिए ताकि दौड़ बराबरी पर समाप्त हो?
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सही उत्तर: (D) 70 m
चाल(Sita):चाल(Radha) = 900:864 = 25:24। चाल(Sita):चाल(Geeta) = 900:756 = 25:21। भाग देने पर, चाल(Radha):चाल(Geeta) = 8:7। 560 मीटर की दौड़ में, बराबरी के लिए, Radha को Geeta को शुरुआत देनी चाहिए = 560×(8−7)/8 = 70 मीटर।
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