SSC CGL Tier-II practice question
In triangle ABC, the altitudes from B and C meet at the orthocentre H. If angle BHC = 140°, find angle A.
From a SSC CGL Tier-II Quantitative Aptitude practice set · Quantitative Aptitude
Tap an option to check your answer.
Show answer and explanation
Correct answer: (D) 40°
Using the standard result angle BHC = 180° − A, we get 140° = 180° − A, so angle A = 180° − 140° = 40°.
हिंदी में प्रश्न
त्रिभुज ABC में, B और C से डाले गए शीर्षलंब लंबकेंद्र H पर मिलते हैं। यदि कोण BHC = 140° है, तो कोण A ज्ञात कीजिए।
उत्तर जाँचने के लिए किसी विकल्प पर टैप करें।
उत्तर और व्याख्या देखें
सही उत्तर: (D) 40°
मानक सूत्र कोण BHC = 180° − A का प्रयोग करने पर, 140° = 180° − A, अतः कोण A = 180° − 140° = 40°।
More solved Quantitative Aptitude questions
- The length of a rectangular field is 25% more than its breadth. If the perimeter of the field is 180 m, find its area.
- Mahendra and Devansh run a manufacturing unit, having invested ₹40,000 and ₹30,000 respectively for the same period. As Mahendra manages…
- The difference between the value of a number increased by 10% and the value of the same number decreased by 25% is 231. What is the number?
- A bank's special savings scheme adds Rs 200 to a customer's balance for each of the first three months. Once the balance crosses Rs 900…
- A bus covers 150 km at 60 km/hr, 120 km at 80 km/hr, 180 km at 90 km/hr without any stops. What is the average speed of the bus for the…
- If 19 men working for 25 days earn Rs. 2000 in total wages, find the total wages earned by 12 men working for 7 days at the same rate.